Need help deriving an equation for electric field created by solenoid

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SUMMARY

The discussion centers on calculating the electric field and force on an electron outside a long solenoid with specific parameters: radius of 4.80 cm, 77.0 turns/cm, and a current ramp rate of 38.0 Amps/s. The induced electromotive force (emf) is calculated using the formula emf = -L * dI/dt, leading to an electric field of 8.27x10^-3 N/C. Consequently, the force on the electron is determined to be 1.32x10^-21 N. The user seeks clarification on deriving the electric field equation and understanding the direction of the force using the right-hand rule.

PREREQUISITES
  • Understanding of solenoid inductance, specifically L = μ₀*N²*A/l
  • Familiarity with electromotive force (emf) and its calculation
  • Knowledge of electric fields and their relationship to voltage (E = V/(2πr))
  • Proficiency in applying the right-hand rule for magnetic forces
NEXT STEPS
  • Study the derivation of the electric field around a solenoid, focusing on E = V/(2πr)
  • Learn about the principles of electromagnetic induction and the role of inductance in solenoids
  • Explore the right-hand rule applications in electromagnetic contexts, particularly for forces on charged particles
  • Investigate the relationship between electric fields and forces on charged particles in varying magnetic fields
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism, as well as anyone involved in solving problems related to electric fields and forces in solenoids.

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Homework Statement


A very long solenoid of circular cross section with radius a= 4.80 cm has n= 77.0 turns/cm of wire. An electron is sitting outside the solenoid, at a distance r= 5.30 cm from the solenoid axis. What is the magnitude of the force on the electron while the current in the solenoid is ramped up at a rate of 38.0 Amps/s?


Homework Equations


emf= -L * dI/dt

F=E*q

L for a solenoid=mu not*N^2*A/l


The Attempt at a Solution


From what another has told me, this is the sequence of steps that works, but I want to know why:
------------------------------
The induced emf is μo*n*A*dI/dt = 4πx10^-7*7400*π*0.0540^2*36 = 3.07x10^-3V

So the electric field = V/2πr = 3.07x10^-3/(2π*0.0590) = 8.27x10^-3N/C

So the force on the electron = E*q = 8.27x10^-3N/C*1.60x10^-19C = 1.32x10^-21N
--------------------------------

I want to start from basics and build the above. So far I start with:

emf= -L * dI/dt

and inductance for a solenoid=mu not*N^2*A/l

so I make:
emf= -mu not*N^2*A/l * dI/dt

now N=number of turns and l=unit length for 1 turn so I can use the above info to turn N/l into the variable n to get rid of l.

So n=N/l and
emf= -mu not*N*(N/l)*A * dI/dt

now I can solve for emf, but I get stuck here because I don't know where E=V/(2pi r) comes from. I need E to plug into F=E*q to get the final answer. I know E=(q/A)/(2*epsilon not), but the only formula I know relating E to V is V= E*d, but I don't think it applies here.

Am I even on the right path to solving this?
 
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I've figured out where I went wrong and had to spend a long time learning more about electromagnetism.

Now I'm struggling to find the direction of the force. I put absolute values in my calculation to avoid sign changes and ended up with a magnitude of 1.28x10^-21N.

Where do I begin to find the direction of the force on the electron?

I recognize there is a b field inside the solenoid going to the right so the force on the electron needs to be such that it makes a b field opposite of this direction to obey the laws of conservation of energy and I know how to do the right hand rule, but don't know how to apply it to this situation. I know direction of B is left, but don't know direction of velocity or force so I don't know how the right hand rule could be used here.

Any help would be appreciated.
 

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