Need help with electric field/potential problem

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SUMMARY

The discussion focuses on calculating the local surface charge density on an irregularly shaped conductor, given electric field values of 56 kN/C and 28 kN/C. The relationship between electric field (E) and surface charge density (σ) is crucial, particularly noting that σ is higher at points of low curvature. The participants emphasize the importance of understanding the formula connecting E and σ to solve for local surface charge density effectively.

PREREQUISITES
  • Understanding of electric fields and potential in electrostatics
  • Familiarity with the concept of surface charge density (σ)
  • Knowledge of curvature in the context of electric fields
  • Proficiency in applying formulas related to conductors and electric fields
NEXT STEPS
  • Study the relationship between electric field and surface charge density using the formula E = σ/ε₀
  • Explore the effects of curvature on electric fields in conductors
  • Learn about the principles of electrostatics in irregularly shaped conductors
  • Investigate practical applications of electric field calculations in engineering contexts
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone involved in electrostatics or conducting materials analysis will benefit from this discussion.

lunarskull
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The problem is defined below:

The electric field on the surface of an irregularly shaped conductor varies from 56 kn/c to 28 kn/c. calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is (a) greatest and (b) smallest.

Attempt at a solution:

Yet to start, b/c don't understand any further steps with such little information

Extra question:

If they only give us 2 numbers of an irregularly shaped object, how are we supposed to manipulate these numbers to find the local surface charge density?
 
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There is a formula connecting E immediately outside the surface of a conductor and sigma (surface charge density). You also should know where the sigma is higher, that is, at points of low or high curvature.
 
thank you for the help, i eventually figured it out because you gave me the general basis that i needed to understand how to answer the problem
 

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