Need help with transfer orbit time period

AI Thread Summary
To calculate the duration of a transfer orbit from Earth to Mars, the semi-major axis of the orbit is given as 190,100,208,000 meters. Using Kepler's third law, the period can be determined by the relationship P^2 proportional to a^3. The user initially calculated P^2 as approximately 6.8699 E 33, leading to an incorrect period value. It is emphasized that Kepler's law requires a constant of proportionality or a ratio with another known orbit to yield accurate results. Understanding these principles is crucial for accurately determining the interplanetary trip duration.
HoboMoo
Messages
2
Reaction score
0
I just don't even know where to begin. I'm not sure what formulas to use and just can't do anyhting with it. any help would be great. Thanks!

Recall that your trip to Mars is accomplished by using an elliptic transfer orbit going from Earth to Mars as shown in Fig. 1. This trajectory assumes that Earth at departure, the Sun, and Mars at arrival, are aligned. You calculated that the semi-major axis for this transfer orbit was a= 190100208000 m.

How long, in days, would the interplanetary trip last? Hint: first, determine the period of the transfer orbit.


untitled.jpg
 
Physics news on Phys.org
How about Kepler's third law?
 
So if a=190100208000m, its P^2=19010020800^3?

If that's the case, i get P^2= 6.8699 E 33 and square root that to get P?

P=8.2885 E 16?
 
Kepler's third law (in its original form) is a law of proportionality, not equality. To make it an equality you would have to use either a suitable (i.e. special) choice of units, a constant of proportionality, or form a ratio with another known pair of semi-major axis and period. So:

$$P^2 \propto T^3 $$
$$P^2 = k\;T^3$$
$$\frac{P2^2}{P1^2} = \frac{T2^3}{T1^3}$$
The last version is probably the easier to use if you happen to know of another suitable body orbiting the Sun for which you know the semi-major axis and the orbital period :wink:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top