Net Ionic Equations: How to Write and Balance Them

  • Thread starter Thread starter oceanflavored
  • Start date Start date
  • Tags Tags
    Ionic Net
AI Thread Summary
The discussion focuses on understanding net ionic equations in the context of an AP Chemistry exam. A participant is confused about the treatment of HF in the ionic equation, questioning why it isn't fully dissociated like HCl. Another contributor clarifies that while HCl dissociates completely in water, HF does not, primarily existing as molecules rather than ions. This distinction is crucial for accurately writing net ionic equations, as it relates to the concept of ionic equilibrium. The conversation highlights the importance of recognizing the behavior of different acids in aqueous solutions.

who's excited for summmerrrr?


  • Total voters
    3
oceanflavored
Messages
44
Reaction score
0
i'm studying for my apchem exam. and rightnow; I'm currently reviewing my net ionic equations. but there's something I'm confused about in my ap chem book.

Homework Statement


the equation is:
CaF2 (aq) + 2HCl (aq) ---> 2HF (aq) + CaCl2 (aq)
and then the book says that the ionic equation is:
Ca2+ (aq) + 2F- (aq) + 2H+ (aq) + 2Cl- (aq) --> 2HF (aq) + Ca2+ (aq) + 2Cl (aq)

i understand when there's a solid (precipitate) you don't write it all out. because it doesn't dissolve. but wouldn't you write 2HF all out, as in you would write: 2H+ (aq) and 2F- (aq), or is there some other rule that i don't know about??

thanks to anyone who can help. i'd appreciate ittt :)
 
Physics news on Phys.org
come on guysssss.you can do this.
i believeeeee.
 
this is a method of extracting hydrofluoric acid! whereby CaF2 is an ore known as fluorite...well coming back to your problem...

As you know, acids exist as molecules in pure state. but when added to water... they dissociate.

e.g. HCl <------> H* + Cl-

HCl dissociates completely (or so) in aqueous mediem i.e water... and so, exists as H* and Cl-

but HF does not dissociate completely. it has a very much lower tendency to ionise in water...and therefore exists mainly as HF molecules instead of H* and Cl-... it's all about ionic equillibrium... in which I'm not very expert!

hope to have helped you
 
oh okayy. thanks.
that helps a lottt :)
thanks superduper much.
ps: were you the one that said "school rocked to the 1000th degree?"
because that's just strangeeeeee.
in a good way :)
 
:confused: nope...i don't think so...duh
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top