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Newton's 2nd Law on light fixture

  1. Oct 2, 2011 #1
    1. The problem statement, all variables and given/known data
    A lightweight string of length 60.0 cm is attached to the ceiling at points separated by distance D, as shown on the diagram in my attachment. Three objects of equal mass are hung from the string, separating the string into four equal segments of lenth L. If θ=40°
    , find the measure of angle phi and the distance D.

    2. Relevant equations

    please see attachment

    3. The attempt at a solution

    please see attachment
     

    Attached Files:

  2. jcsd
  3. Oct 2, 2011 #2
    I also want to say, I've attempted to use only the equations for the sum of y forces on the knots, since I've ruled the masses out as irrelevant, so those free body diagrams are also irrelevant. I subbed the value of T from the middle knot sumFy equation into the T for the 1st knot's sumFy equation and solved for phi. . . wrong answer resulted
     
  4. Oct 2, 2011 #3

    ehild

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    Homework Helper
    Gold Member

    L is the length of the pieces of the string, not the tension in them. The tensions are not the same in the different pieces at both sides of a knot.

    ehild
     
  5. Oct 2, 2011 #4

    NascentOxygen

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    Staff: Mentor

    I'd say that, at each tie point, the two horizontal components of the tensions cancel.
     
  6. Oct 2, 2011 #5
    Thanks,

    So, on my free body diagram on the 1st knot from the left, say I label the mg T, as T1, then T2 (upper left) and T3 (upper right), then for the middle knot, the same T1 from the mg (since equal mass=equal weight), but the tensions on either sides are BOTH T3 (equal, but opposite, right? due to same L)?? That's what I'm going to attempt.
     
  7. Oct 2, 2011 #6

    ehild

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    It will be all right. The right-hand part is mirror image of the left-hand part because of the equal lengths and masses, therefore the tensions are the same in the bottom pieces of the string.

    ehild


    ehild
     
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