Newton's Laws of motion problem

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Homework Help Overview

The discussion revolves around a problem involving Newton's Laws of motion, specifically focusing on a block resting on an inclined plane with applied forces and friction. Participants are exploring the conditions under which the block will not slip down the plane.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss drawing free body diagrams and summing forces in different directions. There are attempts to calculate forces acting on the block, including frictional forces, but some express confusion about the correct application of equations and the direction of forces.

Discussion Status

Some participants have provided feedback on potential errors in the original poster's calculations and have prompted further exploration of the forces acting parallel to the inclined plane. There is an ongoing exchange of ideas without a clear consensus on the next steps.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is a mention of coefficients of friction and angles, which are critical to the problem setup.

sepah50
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Homework Statement



A block weighing 70.0 N rests on a plane inclined at 25.0° to the horizontal. A force F is applied to the object at 35.0° to the horizontal, pushing it upward on the plane. The coefficients of static and kinetic friction between the block and the plane are, respectively, 0.333 and 0.156.

What is the minimum value of F that will prevent the block from slipping down the plane?

Homework Equations



[tex]\sum[/tex]Fy= Sum of all Forces = Newton's Second Law

The Attempt at a Solution



So in the beginning I draw the Angles and make a Free Body Diagram. I sum up all the forces which is
[tex]\sum[/tex]Fy = [tex]\eta[/tex] + Fsin(10) - 70cos(25) = may

may is 0 since block is not moving away from the plane

what I get then is [tex]\eta[/tex]= .173648F - 63.4415

After this point I know I have to find Fsmax which equals [tex]\mu[/tex]s[tex]\eta[/tex]. After this part I get lost but I can't find [tex]\eta[/tex][tex]\mu[/tex]s
From what I remember [tex]\mu[/tex][tex]\eta[/tex]s = mg*sin[tex]\theta[/tex]. Hope somebody can help!
 
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Hi sepah50,

sepah50 said:

Homework Statement



A block weighing 70.0 N rests on a plane inclined at 25.0° to the horizontal. A force F is applied to the object at 35.0° to the horizontal, pushing it upward on the plane. The coefficients of static and kinetic friction between the block and the plane are, respectively, 0.333 and 0.156.

What is the minimum value of F that will prevent the block from slipping down the plane?

Homework Equations



[tex]\sum[/tex]Fy= Sum of all Forces = Newton's Second Law



The Attempt at a Solution



So in the beginning I draw the Angles and make a Free Body Diagram. I sum up all the forces which is
[tex]\sum[/tex]Fy = [tex]\eta[/tex] + Fsin(10) - 70cos(25) = may

may is 0 since block is not moving away from the plane

what I get then is [tex]\eta[/tex]= .173648F - 63.4415

I think you have a couple of sign errors here.

After this point I know I have to find Fsmax which equals [tex]\mu[/tex]s[tex]\eta[/tex]. After this part I get lost but I can't find [tex]\eta[/tex][tex]\mu[/tex]s

When you summed up all the forces, you did it only in the y-direction (perpendicular to the plane). What is the sum of the forces in the x-direction (parallel to the plane)?

From what I remember [tex]\mu[/tex][tex]\eta[/tex]s = mg*sin[tex]\theta[/tex]. Hope somebody can help!
 
Thanks! :)
 
thanks
 

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