Newton's second low 3 connecting objects

  • Thread starter Thread starter Some body
  • Start date Start date
AI Thread Summary
The discussion revolves around solving a physics problem involving Newton's second law and three connected objects. The original poster struggles with multiple unknowns, including tensions and acceleration, and seeks assistance in drawing free-body diagrams to visualize the problem. Participants emphasize the importance of these diagrams to create equations that help eliminate unknowns. After receiving guidance, the poster successfully calculates the tension, weight, and acceleration values. The conversation highlights the effectiveness of free-body diagrams in solving complex physics problems.
Some body
Messages
5
Reaction score
0
Hi,

I have a problem with solving this question. Could anyone help me please.

The question is in this link http://im42.gulfup.com/BWgfE.jpg
 
Last edited by a moderator:
Physics news on Phys.org
Draw the free body diagrams. Make sure you keep in mind that they are not all on a flat surface. Once they are drawn out, seeing how to solve for other things might be easier to visualize.
 
Yosty22 said:
Draw the free body diagrams. Make sure you keep in mind that they are not all on a flat surface. Once they are drawn out, seeing how to solve for other things might be easier to visualize.

I tried for million times , but still can't solve it , I have about 4 anknown things , tension between A and B , mass for object C , tension between B and C , acceleration for the system before and after cutting the rope between A and B
 
You do know the acceleration "before". Read carefully what the problem states about the speed of C.
 
Some body said:
I tried for million times , but still can't solve it , I have about 4 anknown things , tension between A and B , mass for object C , tension between B and C , acceleration for the system before and after cutting the rope between A and B

Have you drawn your free-body diagrams?
These will give you a set of equations which you can use to eliminate some of these unknowns (bearing in mind what voko said about the acceleration).
If you're having trouble with this, show us what you've done.
 
Thank you all for helping me , you are the best, now I could solve the homework the tension will be 8.75 the weight will be 30.52 and the acceleration will be 1.55 .
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top