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NMR analysis help? Lab tomorrow :/

  1. Jun 28, 2011 #1
    1. The problem statement, all variables and given/known data

    It is supposed to be a glycol with a formula of C6H14O2.
    The H NMR integrations are 6H and 1H as indicated on the H NMR.

    The IR:

    The H NMR:

    2. Relevant equations

    IDH = (2+ (2*#C)- #H)/2

    3. The attempt at a solution
    I calculated the IDH to be zero meaning that it is a straight chain.
    My guess is:
    CH3 CH3
    | |
    | |
    CH3 CH3
    I'm not sure if it's right though.
    Thanks a lot to anyone who helps out!!
  2. jcsd
  3. Jun 28, 2011 #2


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    Looks good to me.
  4. Jul 27, 2011 #3
    Thank you so much!
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