You cannot convert a voltage source into a current source. What you can do is to convert a voltage source in series with a resistor into a current source in parallel with the same resistor. This is Norton's theorem.celect said:Can someone direct me to a tutorial for solving network
nodal voltages.
Also need to learn how to convert voltage source to a current source.
No, you must makecelect said:So if I need to find E/Z = 20/9.9 = 2A
Now all I do is redraw circuit with 2A current source with
impedance parallel in circuit?
I have transformed the complex number from its cartesian form to its polar form.celect said:Here is a problem I got wrong, with the solution.
I don't understand how they got answer.
I don understand how you get
5.6 + j8.2 as 9.93 <55.67
how does 5.6 become 9.33
and j.2 = 55.67
[tex]tan^{-1}[/tex] means arctan. It is the arc whose tangent is y/x.celect said:Thanks its coming together now.
so my current = 20/9.93 = 2A
I don't understand how to get degrees yet
[tex]\phi = tan^{-1}\frac{y}{x}[/tex]
do I take 8.3/5,5 tan and then use above formula?
what is the -1 how do i use on calculator?