Normalizing Data from Lens Equation Lab

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Normalizing data in a lens equation lab involves dividing measurements by a relevant characteristic quantity to facilitate comparison across different scenarios. This could mean dividing image lengths by the size of the objects being measured or using a characteristic length related to the lenses involved. The goal is to create a standardized dataset that allows for easier analysis and comparison of results. By applying normalization, data from various experiments can be more effectively evaluated. Understanding the specific context of the measurements is crucial for determining the appropriate normalization factor.
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Can anyone explain how one would normalize data from a lab? We just completed the lens equation lab in class and part of the analysis is to include "normalized" virtual object data in the graph. There are only 4 measurements taken. Any feedback would be great! :shy:
 
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To normalize data often means to divide by some characteristic quantity. For example, in a circuit, we might divide all of the impedances by the characteristic impedance. This might make it easier for us to compare data from many different circuits, with different characteristic impedances.

In an optics lab, I'm not sure what I would normalize by, but it should be something that makes data from different situations easy to compare. For example, if I measured images of various objects, maybe I would divide the lengths by the object size. Or if I used various lenses, maybe I would divide distances by some characteristic length of the lenses...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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