Notation for marking the voltage drop in this picture

AI Thread Summary
The voltage drop notation V_0 in the diagram refers to the potential difference between the two rightmost nodes, as indicated by the context of the circuit. It is common practice to denote voltage across elements in circuit diagrams, and this notation typically signifies the voltage across the associated element, which in this case is the current generator. While there are standard conventions for marking voltages, they may not be universally applied across all circuit diagrams. The discussion highlights that the notation can vary and may not always follow a consistent rule. Overall, the marked voltage indicates the potential difference across the current generator element.
LongApple
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Homework Statement



When we write the V_0 on the right of the diagram as show below, between which two points does the voltage drop refer to? There are two nodes on the top correct? I am assuming the voltage drop refers to the two rightmost nodes.

I've tried to circle the nodes.

See this link:

http://i.imgur.com/kutasHe.png

Homework Equations


It's just a notation question.

The Attempt at a Solution


It's not a homework problem.
 
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LongApple said:
I am assuming the voltage drop refers to the two rightmost nodes.
Good assumption.

Boy, what a lousy problem.
 
What is the rule for the notation in general?

Is it common to just mark voltage as height on the paper as opposed to between specific nodes?
 
Are there standard conventions/notations for circuit diagrams? I'm certain there almost have to be. Are they universally applied? Not in the 50 odd years I've been deciphering them. Check NEMA, IEEE, Giaccaletto, Kaufman & Seidman, who else ...
 
Because it's written beside an element, I'd say in general a marked voltage will be the voltage across that element. Yes, in this case it follows that it's the potential difference between the rightmost nodes.
 
NascentOxygen said:
Because it's written beside an element, I'd say in general a marked voltage will be the voltage across that element.
And that element is the current generator. So the marked voltage is across it.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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