Engineering NPN Transistor Circuit Analysis

AI Thread Summary
The discussion focuses on analyzing a transistor circuit to determine voltage levels and transistor states under two cases. For Case #1, with both V1 and V2 at 0V, the user calculated that the base current (Ib) is 0A, leading to an infinite beta (β), which was corrected to indicate that Ic equals 0. The user successfully calculated the collector current (Ic) for Q3 and found V3 to be 4.51V. In Case #2, where V2 is 5V and V1 is 0V, the user is uncertain about how to proceed, noting that current will flow into the base of Q2. The discussion highlights the challenges of understanding transistor behavior in circuit analysis.
bschwartz
Messages
36
Reaction score
0

Homework Statement


Determine the voltage level at V3. For each case also determine which transistors are on and saturated, on and active, and which are off. Let R1=R2=R3=2.2kΩ and let Rc=240Ω and Vcc=5V. Calculate β for each transistor as well.

We are to assume that if the transistor is on, then it is in the saturated state so Vce=0.2V. If β>20 then the transistor is in active and Vce=2V+. Also, Vbe=0.6V if the transistor is on

Case #1: V1=V2=0V
Case #2: V1=0V V2=5V

wd2cW.png

Homework Equations


Ic=β*Ib
KVL, KCL

The Attempt at a Solution


Ok, so here's what I did for the first case where both V1 and V2 are 0V. Since they are 0V, Ib=0A and therefore β=∞ for both Q1 and Q2, right? If so, then I'm basically left with the "upper" circuit containing Q3 and V3.

I then found Ib=Vcc/(240+2.2k)
Ib = 0.002A

I did the same approach for Ic=Vcc/(240)
Ic = 0.0208A

β=10.1 so Q3 is then on and in the saturated region. To find V3 I simply subtracted the voltage drop of the 240Ω resistor

V3 = 5 - (240*.002A) = 4.51V

I don't know if this is right at all since I've never done any circuit analysis with transistors before. If it's right, I'm still completely lost on how to start Case #2 where V2=5V and V1=0V. Any help is greatly appreciated.
 
Physics news on Phys.org
Your method looks right, though I haven't checked the arithmetic. It is unusual to use β in the two ways you have. Writing β=∞ is not right. Just say IB=0 and therefore IC=β*0=0.

When V2=5v there will be current into the base of Q2, hence collector current, too.
 
excuse me. , where are you find this question. I also need this similar question to finish my homework
 

Similar threads

Replies
15
Views
4K
Replies
3
Views
2K
Replies
4
Views
3K
Replies
1
Views
2K
Replies
4
Views
3K
Replies
5
Views
2K
Replies
12
Views
2K
Replies
6
Views
2K
Back
Top