PROBLEM:the current at the terminals of a certain current source is measured with an ammeter having an internal resistance [tex]R_i=10 ohms[/tex] and is found to be [tex]11.988 mA[/tex] ;adding a [tex]1.2 kilo -ohms[/tex] resistance between the source terminals causes the ammeter reading to drop to [tex]11.889 mA[/tex].Find [tex]i_s[/tex] and [tex]R_s[/tex](adsbygoogle = window.adsbygoogle || []).push({});

NOTE:[tex]i_s[/tex] and [tex]R_s[/tex] constitute a practical current source.i.e [tex]R_s[/tex] is the internalresistance of the source [tex]i_s[/tex]

note:my answers don't quite match with the answer at the back of the textbook....

my calulations: [tex]i_s=11.997 mA[/tex] and [tex]R_s=13200ohms[/tex]

answers in the answer booklet:[tex]i_s=12mA[/tex] and [tex]R_s=10kilohms[/tex]:uhh:

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# Homework Help: Numerical problem about circuits

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