- #1
Sam_The_Great
- 7
- 0
Hello, I have this problem and I want to verify if somebody thinks I did it right.
The figure shown below shows an infinitely long wire carries current I1 = 20A. A short wire of length 9cm lies perpendicular to the direction of the long wire. The nearest end of the short wire is 3 cm away and it carries a current I2 - 5A in the direction show. Thwat is the net force on the short wire?( The magnetic field produced by the infinitely long wire is not uniform)
I = 20 A
------------>---------------->----------------------->----------------
|
| 3cm
|
|
|
| 9cm
down current
|
| I = 5 A
The approach I took was that I said F = Ilb and we know that B = u02I1/4piR
R in this case is y, we know that the change in force dF = I2u02I1/4piy dy and you integrate from .03 to .12. The answer I get is 3.58 N in the x direction. Would this be the right approach?
The figure shown below shows an infinitely long wire carries current I1 = 20A. A short wire of length 9cm lies perpendicular to the direction of the long wire. The nearest end of the short wire is 3 cm away and it carries a current I2 - 5A in the direction show. Thwat is the net force on the short wire?( The magnetic field produced by the infinitely long wire is not uniform)
I = 20 A
------------>---------------->----------------------->----------------
|
| 3cm
|
|
|
| 9cm
down current
|
| I = 5 A
The approach I took was that I said F = Ilb and we know that B = u02I1/4piR
R in this case is y, we know that the change in force dF = I2u02I1/4piy dy and you integrate from .03 to .12. The answer I get is 3.58 N in the x direction. Would this be the right approach?