Op amp bandwidth and gain problem

AI Thread Summary
To calculate the 3dB frequency (F3db) of an inverting op amp, the bandwidth gain product must be considered, similar to a non-inverting op amp. For a non-inverting op amp with a bandwidth gain product of 1.5x10^6 Hz and a gain of 20dB, the F3db is calculated as 150kHz. In contrast, the F3db for the inverting op amp is estimated to be around 136kHz, but the calculation method is unclear to the participants. The difference in gain between non-inverting and inverting op amps is attributed to the resistor ratio used in the external circuit, which affects the cutoff frequency. Understanding these calculations is essential for effective op amp design and application.
greg997
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Could sb explain to me how to calculate the 3db frequency of the inverting op amp, please?

1. For non-inverting op amp
If Bandwidth gain product is 1.5x10^6 Hz and gain is 20dB then the F3db is given by Bandwidth gain product over 20. It equals 150kHz.

2. For inverting op amp the F3db is supposed to be 136kHz. But no idea how to calculate this.

What is the difference in gaing given by non and inverting opamp?

Thanks for help
 
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greg997 said:
Could sb explain to me how to calculate the 3db frequency of the inverting op amp, please?

1. For non-inverting op amp
If Bandwidth gain product is 1.5x10^6 Hz and gain is 20dB then the F3db is given by Bandwidth gain product over 20. It equals 150kHz.

2. For inverting op amp the F3db is supposed to be 136kHz. But no idea how to calculate this.

What is the difference in gaing given by non and inverting opamp?

Thanks for help

What's the external gain for question #2? It appears to be given for question #1 (set by external components).
 
The gain is the same as in example with non inverting op amp. I ve heard that it is about ratio of resistors.It's lower therefore cutoff frequency is lower a bit. But no idea how to calculate this.
 

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