Op-Amp w/ Inductor: vO & vS Relationship

  • Thread starter Thread starter tbrownie
  • Start date Start date
  • Tags Tags
    Inductor Op-amp
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 6K views
tbrownie
Messages
2
Reaction score
0
Alright, so I have a problem on my homework set that features an Operational Amplifier. It's very similar to a "Integrator" Circuit which means the gain would be.. K = -1 / R*C. The problem is, the capacitor has been replaced by an inductor. I'm trying to find the relationship between vO and vS but there is nothing in my book or notes detailing what to do with an inductor in an Op-Amp. I've been searching around for help, and was told to think about how capacitors and inductors are represented in the "s domain." I don't even know what the "s domain" is, this is just a basic ECE 201 class. We just started learning about capacitors, inductors, and Op-Amps. Am I missing something?
 
Physics news on Phys.org
Would the answer be... -L/R * dVs(t)/dt?
 
tbrownie said:
Alright, so I have a problem on my homework set that features an Operational Amplifier. It's very similar to a "Integrator" Circuit which means the gain would be.. K = -1 / R*C. The problem is, the capacitor has been replaced by an inductor. I'm trying to find the relationship between vO and vS but there is nothing in my book or notes detailing what to do with an inductor in an Op-Amp. I've been searching around for help, and was told to think about how capacitors and inductors are represented in the "s domain." I don't even know what the "s domain" is, this is just a basic ECE 201 class. We just started learning about capacitors, inductors, and Op-Amps. Am I missing something?

tbrownie said:
Would the answer be... -L/R * dVs(t)/dt?

Can you show the circuit and how you derived that equation? I think you are on the right track. You just use the "virtual ground" property of the "-" input of the opamp to write the current and voltage equation there...
 
The 's-domain' is the Laplace domain.

Normally when you analyze a resistive Op-Amp circuit you look at the resistances and figure out the transfer function (circuit gain).

Capacitors don't have a resistance per se, they have a reactance. Do you know what the formula is for the reactance of a capacitor, and then what this looks like in the Laplace domain (hint: it will have an 's' variable in it somewhere)?