Optimizing River Crossing Time for a Hunter Using a Powerboat

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SUMMARY

The discussion focuses on calculating the minimum time required for a hunter to cross a river 1.5 km wide using a powerboat with a maximum speed of 12 km/h against a current flowing at 5.0 km/h. The correct resultant velocity of the hunter is determined to be 13 km/h, derived from vector addition of the boat's speed and the river's current. The initial calculation of crossing time incorrectly used the boat's maximum speed instead of the resultant velocity, leading to a time of 0.125 hours for crossing at 12 km/h instead of the accurate time at 13 km/h.

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joe215
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1. Homework Statement

A hunter wishes to cross a river that is 1.5 km wide and flows with a speed of 5.0km/h parallel to its banks. the hunter uses a small powerboat that moves at a maximum speed of 12 km/h with respect to the water. What is the minimum time necessary for crossing?


3. The Attempt at a Solution

5km/h^2 + 12Km/h^2=sq rt 169km/h^2 = 13 km/h

The hunter moves really moves at 13 km/h to the right because of the water moving upstream. 13 is the vector resultant of 5 north and 12 east.

So, T=D/V

T=width of stream/velocity of hunter
T=1.5km/12km/h = 0.125 h
 
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joe215 said:
1. Homework Statement

A hunter wishes to cross a river that is 1.5 km wide and flows with a speed of 5.0km/h parallel to its banks. the hunter uses a small powerboat that moves at a maximum speed of 12 km/h with respect to the water. What is the minimum time necessary for crossing?


3. The Attempt at a Solution

5km/h^2 + 12Km/h^2=sq rt 169km/h^2 = 13 km/h

The hunter moves really moves at 13 km/h to the right because of the water moving upstream. 13 is the vector resultant of 5 north and 12 east.

So, T=D/V

T=width of stream/velocity of hunter
T=1.5km/12km/h = 0.125 h

You calculate the correct velocity of the hunter (V = 13 km/h), but when you calculated his time of crossing you used V = 12 km/h.
 
If I used 13km/h instead of 12km/h, would the answer be right?
 

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