Parallel circuit with internal resistance

AI Thread Summary
The discussion focuses on a parallel circuit with four resistors and an internal resistance of the source. The total resistance of the parallel resistors is calculated to be 2.15 Ohms, leading to a total circuit resistance of 2.65 Ohms when including the internal resistance. The supply voltage is 27V, resulting in a calculated total current of 10.2A. However, the sum of the individual currents through the resistors exceeds this value, prompting questions about the current distribution. The voltage drop across the parallel resistors is determined to be 21.93V, confirming that the voltage does not equal the supply voltage.
dbag123
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Homework Statement
Calculate current through the source
Relevant Equations
P=UI, U=RI
4 resistors R1= 10 Ohm R2= 7 Ohm R3= 6 Ohm R4 = 18 Ohm, internal resistance of source is 0,5 Ohm and supply voltage is 27V

Total resistance in parallel resistors 1/R = 0.465 taking the inverse of that i get 2,15 Ohm. Add to that the internal 0,5 and the total comes out to 2,65 Ohm.

Total current would then be U/R --> 10,2A rounded up. If it is true that in a parallel circuit the voltage stays the same, than it stands to reason that the sum of the currents should add up to 10,2 but they dont. i get a total current of 12,577 just for the 4 resistors. What is happening here?
 
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dbag123 said:
What is happening here?
WHERE? Show a circuit diagram.
 
1570119214640.png
 
If the supply voltage is 27V, the internal resistance is 0.5Ω and the resistance of the parallel set is 2.15Ω, what is the voltage drop across the parallel resistors? (hint: it is not 27V)
 
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21,93V
 
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And if you have a voltage drop of 21.93V across the 4 parallel resistors, what is the total current through them?
 
10,2A
 
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