Parallel-Plate Capacitor Separation

AI Thread Summary
The discussion revolves around calculating the plate separation of a parallel-plate capacitor with a given area and capacitance. The formula used is C = κε0 (A/d), where the permittivity of vacuum is provided. An initial calculation yielded a separation of approximately 0.34 m, but the conversion from cm² to m² was incorrectly applied. The error stemmed from misunderstanding the conversion between square centimeters and square meters. Clarification on proper unit conversion is needed to resolve the calculation issue.
beeteep
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Homework Statement


A parallel-plate capacitor has a plate area of 18.5 cm2 and a capacitance of 4.8 pF
What is the plate separation? The value of the permittivity of a vacuum is 8.8542 x 10-12 C2/N⋅m2

Homework Equations


C = κε0 (A/d)

The Attempt at a Solution


4.8x10-12 = ((8.8542x10-12)(1)(.185)) / d

d = .341255625 m
 
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The conversion from cm2 to m2 is not correct.
1 cm = .01 m, but 1 cm2 ≠ .01m2.
 
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Likes beeteep
I didn't know there was a difference between converting between cm2 and m2. I'll need to do a little more digging on how to properly convert between those, but you are correct. That was my issue. Thanks for your help!
 

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