Particle moving in a circle (angular momentum)

AI Thread Summary
When a particle moves in a circle, its angular momentum is calculated using the formula L = m r² ω. If the radius of the circle is doubled while maintaining the same angular speed, the angular momentum will indeed increase. Specifically, the new angular momentum will be four times greater, not just doubled, due to the squared relationship with the radius. The confusion arises from misapplying the formula, as the correct interpretation shows that L is proportional to the square of the radius. Understanding this relationship is crucial for accurately calculating angular momentum in circular motion.
preluderacer
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Homework Statement



A particle is moving in a circle. If the radius of the circle is doubled and the angular speed remains the same, then the angular momentum of the particle about the center of the circle will also be doubled.



The Attempt at a Solution



Im thinking it's false because the equation mr^2(angular speed). I am not quite sure though if this was the equation to use though.
 
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You are correct, the angular momentum is L=m r w = m r^2 w.

ehild
 
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