Calculating Speed of Simple Pendulum at 25° Angle

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To calculate the speed of a simple pendulum at the bottom of its swing, the problem involves a pendulum of 2.0 m length released from a 25° angle. The correct speed at the lowest point is determined to be 1.9 m/s, while the initial calculations yield 1.8126 m/s. The discrepancy arises from the use of conservation of energy, where the potential energy at the highest point is equated to the kinetic energy at the lowest point. The vertical height change is calculated as 2 - 2*cos(25°). Properly applying these principles will yield the accurate speed of the pendulum.
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Homework Statement



A simple pendulum, 2.0 m in length, is released from rest when the support string is
at an angle of 25° from the vertical. What is the speed of the suspended mass at the
bottom of the swing?

Homework Equations



R2= X2 + Y2

The Attempt at a Solution



I know the answer is 1.9ms-1

but i keep getting 1.8126ms-1

which is 2.cos(25)
what am i doing wrong?
 
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If you are going to use conservation of energy, for example, then you equate the k.e. at the lowest point to the p.e. at the highest.
The mass has risen a vertical height 2 - 2.cos25. when moved to its starting point.
 

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