Period of a Physical Pendulum: Finding T for a Uniform Disk

AI Thread Summary
To find the period T of a uniform disk oscillating as a physical pendulum about an edge axis, the moment of inertia I must be calculated using the formula I = (3/2)MR^2, applying the Parallel Axis Theorem. The period is given by T = 2π√(I/mgd), where d is the distance from the center of mass to the axis of rotation. The user initially calculated T as 3.2 seconds but found this result incorrect. It is suggested to simplify the expression for the moment of inertia symbolically before substituting numerical values to minimize errors. The discussion emphasizes the importance of careful calculation in determining the correct period for small oscillations.
yaylee
Messages
22
Reaction score
0

Homework Statement


A uniform metal disk (M = 9.81 kg, R = 8.99 m) is free to oscillate as a physical pendulum about an axis through the edge. Find T, the period for small oscillations.


Homework Equations



I (uniform disk, with axis through center of mass) = (1/2)MR^2
T = 2π√(I/mgd), where d = distance from center of mass to point of rotation (axis)
I (uniform disk, with axis through the edge = (3/2)MR^2, after using Parallel Axis Theorem:
I (center of mass) + Md^2, where d = RADIUS of the disk:

The Attempt at a Solution


Plugging in for T, we have 2π√(I/(9.81)(9.81)(8.99).
After plugging in I = (3/2)*(9.88)*(8.99)^2, we can plug and chug away:

T = 3.2 seconds, however, this was incorrect.

I was wondering where I went wrong here, thanks again !
 
Physics news on Phys.org
You might find that fewer "finger" errors can creep in if you carry out more of the process symbolically before plugging in numbers.

Put your expression for the moment of inertia into the expression for the period and simplify before going numerical :wink:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top