What is the Minimum Distance x for an Interrupted Pendulum to Wrap Around a Rod?

  • Thread starter Thread starter Bob Jagnaf
  • Start date Start date
  • Tags Tags
    Pendulum Period
AI Thread Summary
An interrupted pendulum changes its trajectory when the string strikes a rod below the pivot point, leading to a smaller radius of motion. The key to determining the minimum distance x for the pendulum bob to completely wrap around the rod involves calculating the energy required to maintain circular motion without transitioning into free fall. The discussion emphasizes breaking the problem into two phases: the initial swing towards the rod and the subsequent rotation around it. Understanding the equations governing both phases is crucial for finding a solution. Clear guidance is sought on the necessary calculations and principles involved in this scenario.
Bob Jagnaf
Messages
1
Reaction score
0
An interrupted pendulum is one in which the string strikes a rod directly below the pivot point causing the pendulum bob to deviate from its previous circular trajectory into a trajectory of a smaller radius. Depending on the original angle of displacement θ and where the rod is placed relative to the total length of the string, the bob may or may not wind itself completely around the rod.

Calculate the minimum distance x in terms of L and θ that will cause the pendulum bob to completely wrap around the rod. You should be careful here – the bob must have sufficient energy to completely circle the rod, and not enter a projectile motion pattern of free fall.

Any solutions is appreciated, steps to solutions are very valuable. Thanks!
1. Homework Statement


L= total length of string to center of mass from the inital point of the pendulum.

Homework Equations



I found the period of a interrupted pendulum. That is all I have.

The Attempt at a Solution

I am totally lost on how to do this. Can anyone guide me?[/B]
 
Physics news on Phys.org
It is not enough to say you are completely lost. You must have done some previous work with pendulums, so should have some expressible thoughts.
I'll give you this tip: think of it as two separate phases.
In the first, the pendulum is swinging down towards the rod. Since the rod has not been reached, it plays no part. What equation describes this phase?
In the second, it has reached the rod and is starting to rotate about it. What part of the set up can be ignored in this phase?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
9
Views
2K
Replies
4
Views
2K
Replies
2
Views
6K
Replies
31
Views
7K
Replies
11
Views
3K
Replies
14
Views
2K
Back
Top