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Phase change phenomena in Fluent v15

  1. May 4, 2016 #1
    Hello everyone,
    I am beginner in fluent v15, and I want to simulate the temperature change as a function of time in the phase change materials "PCM" and the heat thermal fluid "HTF" and the PCM fusion Front.
    Regarding the geometry I chose to work with two coaxial tubes: the inner tube contains the heat thermal fluid and the outer tube contains the PCM
    for meshing I appointed the input, output and symmetry area of HTF and PCM. Also the entry, exit and the symmetry of the wall between the PCM and the HTF
    The set up steps followed are:
    General ==> Type: based pressure, velocity formulation: absolute, time: transient
    Model ==> volume of fluid with 2 stages in number eulerian, energy, melting and solidification
    Materials ==> PCM characteristics: density, solidius and liquidus temperature , thermal conductivity, pure solvent latent heat and thermal expansion coefficient
    for the HTF I chose to work with liquid water
    Phases ==> Primary phase pcm, Secondary phase HTF
    Cell Condition box ==> Wall (phase mixture, Type: Solid)
    HTF (phase mixture type: Fluid, Fluid porosity: 1)
    PCM (phase mixture type: Fluid, Fluid porosity: 1)
    NB: I want to determine the porosity of the fluid depending on the temperature f (T)
    - f(T) = 0 if T < Ts
    - f(T) = 1 if T > Tm
    - 0 < f(T) = (T -Ts) / (Tm - Ts ) < 1 if Ts < T < Tm
    but I don't know how to do it with new input parameter
    Boundary Conditions ==> in this stage I entered the HTF input velocity and the inlet and outlet temperatures of the HTF, PCM and WALL but I find myself stuck facing problem with the symmetry area of HTF and PCM.
    and other boundary conditions appear as: wall-htf-wall, wall-htf-shadow-wall, wall-pcm, wall-pcm-wall, wall-pcm shadow-wall, wall-wall
    but I do not know what to choose for thermal conditions: temperature convection heat flow or or ...
    and if for example I chose the heat flux how can I calculate the heat generation rate and the heat flux.

    I will be very grateful for your help and thank you in advance.

    Best regards;
     
  2. jcsd
  3. May 9, 2016 #2
    Thanks for the post! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
     
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