Phase Difference Problem, Ratio of I/Io

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SUMMARY

The discussion centers on calculating the ratio of intensity (I) at a specific point to the intensity at the center (Io) of a bright fringe in a double-slit interference pattern. The relevant equation is I/Io = cos²(φ/2) * (sin(B/2)/(B/2)), where φ is the phase difference and B is defined as (2πd/λ) * Y/L. The user expresses confusion regarding the application of the equation and the terminology used, specifically "this point" and "bright bridge," indicating a need for clarification on these concepts.

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  • Familiarity with wave optics terminology
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Homework Statement


What is the ratio of the intensity at this point to the intensity at the center of a bright bridge


Homework Equations


GIVEN:
Wavelength=6.9x10^-7m
d=0.00014m (distance between slits)
L=12m (Length to screen/point)
Y=14mm

EQUATION:
I=Io cos^2(phi/2) [(Sin (B/2))/(B/2)]
I/Io=cos^2(phi/2) [(Sin (B/2))/(B/2)]

The Attempt at a Solution




I have phi, solved for b/2 and plugged it in and did everything.

I STILL GOT IT WRONG??! is my equation wrong??
 
Physics news on Phys.org
Where is "this point" and what's a "bright bridge"?
 

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