Photoelectric effect and determining the planckconstant

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SUMMARY

The discussion focuses on determining Planck's constant through the photoelectric effect experiment. The kinetic energy (Ek) of expelled electrons was measured at various frequencies (f) of light, with the equation Ek = h(f - fw) being central to the analysis. The participants clarify that the slope of the graph of Ek versus (f - fw) directly represents Planck's constant (h). Additionally, the relationship between frequency and energy is emphasized, highlighting that while kinetic energy increases, it does not scale linearly with frequency.

PREREQUISITES
  • Understanding of the photoelectric effect and its equations
  • Familiarity with kinetic energy and photon energy concepts
  • Knowledge of graphing data and interpreting slopes
  • Basic principles of momentum in particle physics
NEXT STEPS
  • Study the derivation of the photoelectric effect equation Ek = h(f - fw)
  • Learn how to graph kinetic energy versus frequency to determine Planck's constant
  • Explore the relationship between frequency and energy in quantum mechanics
  • Investigate momentum conservation in particle collisions, particularly in photon emissions
USEFUL FOR

Students and educators in physics, particularly those studying quantum mechanics and the photoelectric effect, as well as researchers interested in experimental methods for determining fundamental constants.

Nikitin
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Homework Statement


In an experiment with the photoelectric effect, the kinetic energy of the expelled electrons was measured. Draw a graph using this data and find the Planckconstant.

Data:
f(1014)hz : 5, 7, 9, 11
Ek(10-18)J: 0.07,0.19,0.3,0.43

Homework Equations


well, Ek + W = hf where Ek is the kinetic energy of the electron, W= the energy needed to liberate it and hf the energy of the photon hitting an atom.

The Attempt at a Solution



As far as I know, one can simplify the above formula to Ek=h(f-fw) where fw is the frequency needed to liberate the electron in the first place. To determine Planck's constant I thought about ΔEk/Δ(f-fw) but I'm a bit confused since Ek isn't proportional to f, but to (f-fw) I'm not sure if that's going to make any difference tho..

So, am I on the right track?

thx 4 all help in advance.
 
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Did you draw the graph? That could be helpful.

Anyway, look at the equation you wrote:
K=h\nu-\phi=h\nu-h\nu_f
What's the relationship between the frequency \nu and the energy?
 
v=K/h + vf

vf remains constant while K increases, but when v increases by a factor of 10, this doesn't mean that K will increase by a factor of 10...
 
Last edited:
Electron/Positron Impact & Photon Energies

BTW, can you help me with another thing? "An electron and a positron are moving against each other. at the point of impact both have the velocity 0.6c

Two gamma photons are sent out. What is each of theirs energy?"

Well, the sum of momentum equals zero in both cases and thus the momentum of each of the photons must equal [lorentzfactor]*9.11*(10^-31)*1.8*10^8 = 0.615*10^-13. But the book says I'm wrong with the momentum. Please help with this...

You'd better move the second question and write it in a new topic.

Returning to the photoelectric problem,
K=h\nu-h\nu_f is in the same form as y=mx+q, where m=h.

What does this suggest you?
 
Last edited by a moderator:
ah right. thanks, i forgot about that. so h equals the growth rate
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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