Physical Chemistry 1st Law of Thermo

AI Thread Summary
The discussion revolves around calculating the final temperature of nitrogen gas (N2) in two different containers after adding 1000 J of energy. In the first container with fixed volume, the internal energy change (ΔU) equals the heat added (q), allowing the use of the equation ΔU = nCvΔT to find the temperature increase. In the second container with a movable piston, the heat added is converted into both work and internal energy change, complicating the calculation. Participants express uncertainty about which equations to apply and how to account for pressure changes in the second scenario. The thread seeks guidance on these thermodynamic principles to solve the problem effectively.
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Homework Statement



Two containers each contain 0.500 moles of N2 initially at 300. K. One container has a fixed
volume, and the other container has a movable frictionless piston. If both containers are heated
by 1000. J energy, calculate the final temperature of N2 for each container.


Homework Equations



PV=nRT

\DeltaU=q+w

Cv for a diatomic molecule is 5R/2


The Attempt at a Solution



I don't really know how to approach this problem as no pressure or volume is given. For the first container, I realize that the volume is fixed, so no heat is lost to work. I don't really know where to go on from here though. Can I say \DeltaU=q and then set nCv\DeltaT=q=1,000?
 
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For the second container, can I assume that pressure will be held constant as the volume of the container increases? The heat put into the system will then be converted into work as well and so \DeltaU will equal q+w. The temperature will increase, but not as dramatically as the first container. I don't know what to do from here though. I don't know which equation I should start with. If someone can point me in the right direction or correct me if I'm wrong, I'd greatly appreciate it. Thanks in advance!
 
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