[Physics Honors] Finding magnitude

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SUMMARY

The discussion centers on calculating the magnitude of a horizontal force required to prevent a 60 N block from sliding down a 30-degree ramp. The correct magnitude of the horizontal force is 35 N, while the user initially calculated it as 25.98 N. The user successfully determined the normal force to be 51.96 N and confirmed that the net force is zero. The key takeaway is that the horizontal force must equal the component of gravitational force acting along the ramp to maintain equilibrium.

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Homework Statement


A 60 N block sits on a ramp slanted at 30 degree. A horizontal force is applied to the block to prevent it from moving. What is the magnitude of the force?

Homework Equations

The Attempt at a Solution



I found the normal force to be 51.96 N (checked it with the answer) and the net force to be 0 (checked with answer as well). But the last part, finding the magnitude of the horizontal force, doesn't seem to make sense to me.

The answer says it's 35 N, but what I got was 25.98 N. picture I tried to draw to show what i did --- > http://puu.sh/bZVT5/0d077890a0.png

I used relative triangles and geometry to determine the angles. Any help would be appreciated on where I went wrong. Thank you.
 
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I don't know how to delete threads, but I figured out how to find the solution to this problem.
 
You have found the component of the force of gravity along the ramp. The component of the horizontal force along the ramp must cancel this exactly.
 

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