Thread Spool Resting on Table: Understanding Lever Arm and Torque

  • Thread starter Thread starter kris_h41
  • Start date Start date
AI Thread Summary
In the scenario of a thread spool resting on a flat table, pulling at an angle causes the spool to slide without rotating, indicating that the lever arm is small but not zero, resulting in zero torque. The discussion questions whether a frictionless table affects the angle of pull, suggesting that a 45-degree angle could create equal sine and cosine values. Participants explore the implications of torque and lever arms in this context, emphasizing the relationship between force application and spool movement. The concept of torque being zero while the spool slides is examined, raising questions about the physical feasibility of such a situation. Understanding these dynamics is crucial for grasping the principles of torque and lever arms in physics.
kris_h41
Messages
2
Reaction score
0
a common thread spool rests on a flat table. you gentyly pull at an angle on a short piece of thread attached to the spool that causes the spool to slide withouut rotating. with the thread arm at this ange the lever arm is??

a- small, but not zero, and the torque is zero
b- perpendicular to the applied force
c-small and the torque is also small
d-zero and their is no torque produced by your pull
 
Last edited:
Physics news on Phys.org
Is such a thing physically possible?
 
I think that the angle would be 45 degrees because in this problem, with a frictionless table, sinx = cosx
 
Is the table frictionless?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top