Polar Coordinates volume question

gr3g1
Messages
71
Reaction score
0
http://containsno.info/mq.JPG

The problem says evaluate the double integral (x + y)dA over the dark region shown in the Figure:

I set up the integrals like this:

\int_{0}^{\pi /2}\int_{2sin\o }^{2} (rcos\o + rsin\o)rdrd\o

Is this correct?

Thanks a lot everyone
 

Attachments

  • mq.PNG
    mq.PNG
    1.1 KB · Views: 429
  • mq.JPG
    mq.JPG
    5.4 KB · Views: 394
Last edited by a moderator:
Physics news on Phys.org
i can't see your pic, but the limts on you intergration say its:

the +x, +y quandrant (0,pi/2)
and the radius varies from the curve defined by r = 2sin(phi) and the circle of radius 2
 
looks ok to me...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top