Polar Coordinates volume question

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SUMMARY

The discussion focuses on evaluating the double integral of the function (x + y) over a specified region in polar coordinates. The integral is correctly set up as \int_{0}^{\pi /2}\int_{2sin\o }^{2} (rcos\o + rsin\o)rdrd\o, where the limits of integration are defined for the first quadrant (0 to π/2) and the radius varies between the curve r = 2sin(\phi) and the circle of radius 2. Participants confirm the setup is accurate for the given problem.

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http://containsno.info/mq.JPG

The problem says evaluate the double integral (x + y)dA over the dark region shown in the Figure:

I set up the integrals like this:

\int_{0}^{\pi /2}\int_{2sin\o }^{2} (rcos\o + rsin\o)rdrd\o

Is this correct?

Thanks a lot everyone
 

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i can't see your pic, but the limts on you intergration say its:

the +x, +y quandrant (0,pi/2)
and the radius varies from the curve defined by r = 2sin(phi) and the circle of radius 2
 
looks ok to me...
 

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