Postion vs time graph without time or initial speed?

In summary, you use Coulombs law to calculate the force between particles 1 and 3, and Newton's laws of motion to calculate the acceleration of particle 3.
  • #1
Cosmik11
2
0

Homework Statement

Consider the system shown to the right. Particles 1 and 2 are fixed in place while particle three is placed at the location shown and released.

image?w=375&h=85&rev=200&ac=1.png


  1. Let’s look at the mechanics of q3, which has a mass of 3.00 X 10-5 kg.
    • What will be the net force on q3?
    • What will be q3’s acceleration?
    • Can you use the acceleration equation [x(t)=1/2at^2+v0t+x0] to predict where q3 will be after 0.50 seconds? Explain.
  1. Project: You al make a spreadsheet that graphs q3’s position vs. time. Here are the requirements:
    • Spreadsheet accurately models the movement of particle 3.
    • You can adjust the magnitude and sign of each of the charges.
    • You can adjust the initial position and mass of q3 (including to the left or right of both charges or right in the middle).

Homework Equations


How would i make the graph without time or any intial or final speed? do you assume that initial speed is 0?

The Attempt at a Solution


i solved for the fnet on 3 through coulomb's law and then plugged the net force into the equation F/M=a to find the acceleration. but i was not really sure where to go from there? I am not really wondering about the spread sheet as to what equations would i use to create a x VS t graph?
 
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  • #2
Welcome to PF;
How would i make the graph without time or any intial or final speed?
You sketch it ... however, in this case the initial speed is implied in the problem statement.
...do you assume that initial speed is 0?
I never "assume". That would make a <donkey> out of u and me ;)

You look in the problem statement for clues - you should never assume anything without a good reason to do so.

In this case the problem statement says that the particle is "placed" and then "released".
Consider the system shown to the right. Particles 1 and 2 are fixed in place while particle three is placed at the location shown and released.
In English, this sort of construct is usually intended to imply that it was initially held stationary (if it was not held, then how can it be "released"?). If it was intended to say that it had some initial velocity the they would say the object was "fired" or "thrown" or some other word would be used that implies movement. If you look through all other problems involving motion that you have done, you should see this is almost always the case.
(Though the statement I quoted could be a translation - in which case: look to the linguistic conventions for the original language.)

i solved for the fnet on 3 through coulomb's law and then plugged the net force into the equation F/M=a to find the acceleration. but i was not really sure where to go from there? I am not really wondering about the spread sheet as to what equations would i use to create a x VS t graph?
The force depends on position. You have the initial position and velocity - and you know how Coulombs law applies to each point on the diagram.
The next equation you need is Newton's laws of motion ... and the suvat equations.
The assignment is to do the problem numerically using the spreadsheet ... you have probably had some example from classwork to help you.
Part of the assignment is to figure out how to use these so we are limited in how much to help you ... show us how you are thin king and we can nudge you when you get confused.
 
  • #3
I know how to get on a spreadsheet i would think but I can't really put it on a spreadsheet if i don't know how to do it by hand. I take AP physics E&M which i am fairly good at but i always hated mechanics so that is why I might sound like i am a little more lost than i should be. I apologize. at my school juniors take pre-calc I take advanced pre-calc, since the school year is still young I don't really know that much calculus so maybe my derivatives were wrong nevertheless this is what I was thinking.

  1. q1*q3*k/(r^2)= F1_3(this is the electric force between 1 and 3)
  2. q2*q3*k/r^2)= F1_2(force between particle 1 and 2)
  3. from there i can find the net force between the two charges with f1_3+f1_2=fnet
  4. with the net force i would then find the acceleration using a=fnet/m (with m being the mass. (now everything above i was okay with doing but now here's where i get confused)
  5. take the acceleration and find velocity. v=-(at) being time intervals (i got that equation aver deriving it from the equation in step 6 and the intial equation was x(.05)=at+v
  6. take that velocity and previous acceleration and find new position: x=1/2at^2+v*t+x
  7. the value for x becomes the new position for particle 3 and now i go back to to the top in order to calculate electric force then acceleration etc rinse and repeat.

the equations that i used derived them from suvat equation x=1/2at^2+v*t+x to find the values i needed. My position value for .00-.05 value didn't make sense because it equated to about 2000 meters I am not understanding where i went wrong. my process went like this:

F1-3=-899 X componet
F2_3= -4495 X componet
Fnet3- 5394 N
A=F/m or -5394/3E-5= -1.798E8
from here this what i did since the problem wants a x vs t graph i decided to do the t in intervals
x(.05)=a
x(.05)=at+v (here is where i get my velocity which is a whopping 8990000.0
x(.05)=.5*-1.798E8*.05^2+ 8990000.0 *.05+.01
this value of x equates to 224750 but how can the particle move to such a high value i know that something is off i just can't find it.
Note: forgot to say i used the distance from 1-3 .01 meters and the distance from 2-3 .004 meters

but if that value was to make sense i would take that x and put that as the new position of q3 and then do the distances between the charges again find fnet again new acceleration etc. and then repeat the process of equations till I have done as many time intervals as necessary.
 
Last edited:
  • #4
It helps to define a coordinate system, and use consistent notation. Here, let me help:

ie. x is the distance between q3 qnd q1. The d=14cm is the distance between the fixed charged.
Now you can talk about the distances properly (your 1 and 2 use the variable "r" to refer to different distances).
##F=kq_3(1/x^2 - 1/(d-x)^2)## ... and x is a function of time x(t).

You are going to divide time into discrete "snapshots" some small time-step ##\delta t## apart.
So define: ##t_n=t_0+n\delta t##, start the motion so that ##t_0=0##

It follows that: ##x_n=x(n\delta t), x_0=x(0)=10\text{cm}## ... see how that works?
Also: ##v_n=v(n\delta t), v_0=0,\; a_n=a(n\delta t)\cdots## ... so what is ##a_0##?

Using this notation you should be able to relate ##a_1## to ##a_0## and, more generally, ##a_{n+1}## to the values before it. Same with the other variables.
You have basically done that in your list above, but it helps to have a notation that makes it clear where you are going.

In your spreadsheet... you need to work out how to generate the values.
How that happens depends on the spreadsheet ...
In general you will want the columb letter to correspond to a physical quantity, and the row number corresponding to the value of "n" in the above notation.
So if A is time, then A0 may be ##t_0## (though that leaves no room for headings and titles).
You can find out how to write equations into cells in terms of other cell-identifiers and make that general by copy-down or something.
 

1. What is a position vs time graph without time or initial speed?

A position vs time graph without time or initial speed is a graphical representation of an object's position as it changes over time, but without specifying the specific time or initial speed at which the object started moving.

2. How is a position vs time graph without time or initial speed different from a regular position vs time graph?

A regular position vs time graph includes specific time values on the x-axis and the initial speed of the object on the y-axis. However, a position vs time graph without time or initial speed only shows the position of the object without any specific time or initial speed information.

3. What information can be determined from a position vs time graph without time or initial speed?

A position vs time graph without time or initial speed can still provide information about an object's motion, such as its direction of movement and the distance traveled. It can also show if the object is accelerating or decelerating based on the shape of the graph.

4. How can a position vs time graph without time or initial speed be used in scientific research?

In scientific research, a position vs time graph without time or initial speed can be used to analyze an object's motion and make predictions about its future movement. It can also be used to compare the motion of different objects and determine which one is moving at a faster or slower rate.

5. How can a position vs time graph without time or initial speed be used in everyday life?

In everyday life, a position vs time graph without time or initial speed can be used to understand the motion of objects around us, such as cars on a highway or a ball being thrown. It can also be used to plan the movement of objects, such as predicting the time it will take for a train to reach a certain destination.

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