Understanding Potential Difference in Terms of Electric Field and Distance

AI Thread Summary
The discussion centers on the calculation of potential difference (ΔV) using electric field (E) and distance (Δx). The user questions the book's solution, asserting that their calculations of Δx and ΔE are correct, leading to a ΔV of -200 V. They highlight a misunderstanding in the book's representation, noting that the vertical axis should reflect V/m, indicating the rate of change of voltage with distance rather than voltage itself. The conversation emphasizes the importance of correctly interpreting the graph to derive accurate results. Understanding these distinctions is crucial for grasping the relationship between electric field, distance, and potential difference.
Miike012
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I posted the question and the answer from the book inside the paint document.

My question is why is the answer not...

Δx = 3-1 = 2m
ΔE = 200-0 = 200V/m

ΔV = -(Area under E vs x graph) = -Δx*ΔE/2 = -200 V
 

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Miike012 said:
I posted the question and the answer from the book inside the paint document.

My question is why is the answer not...

Δx = 3-1 = 2m
ΔE = 200-0 = 200V/m

ΔV = -(Area under E vs x graph) = -Δx*ΔE/2 = -200 V
Your answer looks right to me.

What the book has for a solution is bizarre .
 
The vertical axis isn't Volts it's V/m (eg the rate of change of V with distance).
 

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