Power Factor and Single Phase Transformer

AI Thread Summary
The discussion focuses on calculating the secondary current of a single-phase transformer supplying 120V to a 16kW reactive load with a power factor angle of 40°. The calculation shows that the apparent power (kVA) is 20.89, derived from the formula 16kW divided by the cosine of 40°. The resulting secondary current (Is) is calculated to be 174A using the formula Is = 1000 * kVA / 120V. There is a question about the relevance of the 480V line, but it is clarified that it is not needed for this specific calculation. The calculations provided are confirmed to be correct for determining the secondary current.
fatmoe
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What is the secondary current in a single-phase distribution transformer that is attached to a 480v line when the transformer is supplying 120v to a 16kW reactive load with a power factor angle of 40°.

So I have kVA = 16kW/cos 40 = 20.89kVA

Is = 1000 * 20.89kVA / 120v = 174A.

I don't know if I did this question correctly. Do you not have to use the 480v for anything?
 
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Hi fatmoe,

In future please retain and use the Homework Format Template provided when you start a new thread in the Homework Help sections of PF.

fatmoe said:
What is the secondary current in a single-phase distribution transformer that is attached to a 480v line when the transformer is supplying 120v to a 16kW reactive load with a power factor angle of 40°.

So I have kVA = 16kW/cos 40 = 20.89kVA

Is = 1000 * 20.89kVA / 120v = 174A.

I don't know if I did this question correctly. Do you not have to use the 480v for anything?

Your calculation looks fine for finding the magnitude of the current in the secondary.
 

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