Power of a Pump draining a flooded basement

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The discussion focuses on calculating the power delivered by a pump draining a flooded basement, using principles of fluid dynamics. The pump expels water at a velocity of 5.7 m/s through a hose with a radius of 1.01 cm, and the water is lifted 2.96 m. Initial calculations yield a power output of approximately 52.99 Watts, but participants note discrepancies in their results, with one suggesting a corrected value of 54.07 Watts. The conversation emphasizes the importance of precision in calculations and the need to consider significant figures. Ultimately, the participants are seeking clarity on the correct power output of the pump.
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Homework Statement



Water is pumped steadily out of a flooded basement at a speed of 5.7m/s, through a uniform hose of radius 1.01cm. The hose passes through a window 2.96m above the waterline. What is the power (in W) delivered by the pump?


Homework Equations



Continuity and Bernoulli principles

The Attempt at a Solution



By using the radius, the cross sectional area is found to be 3.2047 * 10^-4 m^2.
Multiply this by the velocity to find the flow rate I got: .001827 m^3/s or 1.827 kg/s.
Multiply this by gravity (9.8 m/s^2) and the height (2.96m), I got 52.99 Watts.

I don't know where I made a mistake, please help!
 
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Your method is right but I get 54.07 ( how many figures did you carry through the calcs?)
 
I tried 54.07 W but it's not correct either.
 

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