Preparing a Solution using ppm and ppb -

AI Thread Summary
To prepare a 50 ppb Pb standard solution in 1% HNO3, the user calculated the required volumes using the dilution formula C1V1 = C2V2, determining that 0.05 mL of a 50 ppm Pb stock solution mixed with 49.95 mL of HNO3 would suffice. However, there was confusion regarding the meaning of "50.0 g" in the instructions, as it could imply the mass of the solution rather than the solute, leading to concerns about the practicality of the dilution. Some participants highlighted that at such low concentrations, adsorption of the solute on container surfaces could affect accuracy, suggesting that gravimetric preparation might be more appropriate. The user sought clarification on whether their calculations were correct and planned to confirm the intended meaning of "50 g" with the instruction source. Overall, the discussion emphasized the importance of understanding solution preparation methods and the implications of concentration units.
Zghakt
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I would like to prepare 50.0 g of 50 ppb Pb standard solution in 1% HNO3 gravimetrically, in a 50.0mL plastic tube from a stock solution of 50 ppm Pb.

From what I understand, this is a dilution...so C1V1 = C2V2

I like working in mg/L more than ppb and ppm so I converted

50 ppb = 0.05 mg/L
50 ppm = 50 mg/L

C1V1 = C2V2
50 mg/L V1 = (0.05 mg/L)(0.05L)
V1 = 0.00005L or 0.05 mL

so then 0.05 mL of 50 ppm Pb and 49.95 mL of HNO3.
Would this be the proper way to prepare this solution?
 
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Zghakt said:
gravimetrically

Zghakt said:
0.05 mL of 50 ppm Pb and 49.95 mL of HNO3
"Gravimetrically?" Or, by volume? At this concentration, a significant fraction of solute is going to be adsorbed on the surfaces of vessels/flasks/containers; are you concerned, or have you made allowances for such an effect?
 
Bystander said:
"Gravimetrically?" Or, by volume? At this concentration, a significant fraction of solute is going to be adsorbed on the surfaces of vessels/flasks/containers; are you concerned, or have you made allowances for such an effect?

This is my first time preparing a solution given the above directions. My instructions stated to prepare the solution gravimetrically. However, I could only figure out how to prepare the solution by volume, ie: 0.05 mL of 50 ppm Pb and 49.95 mL of HNO3. Would you suggest there is a more effective way to make the solution?
 
Zghakt said:
I would like to prepare 50.0 g of 50 ppb Pb standard solution in 1% HNO3 gravimetrically, in a 50.0mL plastic tube from a stock solution of 50 ppm Pb.

From what I understand, this is a dilution...so C1V1 = C2V2

I like working in mg/L more than ppb and ppm so I converted

50 ppb = 0.05 mg/L
50 ppm = 50 mg/L

C1V1 = C2V2
50 mg/L V1 = (0.05 mg/L)(0.05L)
V1 = 0.00005L or 0.05 mL

so then 0.05 mL of 50 ppm Pb and 49.95 mL of HNO3.
Would this be the proper way to prepare this solution?

I doubt you do want to prepare 50 g at 50 ppb - that would be a billion liters wouldn't it?

You had better state or find out what you mean by a billion as there are two different meanings round.

If it is thousand million then you have tondilut your 50 ppm a thousand times. Burt I'm not sure you knows what this means.
 
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epenguin said:
I doubt you do want to prepare 50 g at 50 ppb - that would be a billion liters wouldn't it?

I suppose 50 g refers to the mass of the solution, not of the solute.
 
I misread and thought it was saying 50g of Pb! He also says 50 ml. For his practical purposes I guess it is good enough to. Insider these two the same thing.
 
epenguin said:
I misread and thought it was saying 50g of Pb! He also says 50 ml. For his practical purposes I guess it is good enough to. Insider these two the same thing.

Okay, does this mean the original calculations I posted (see first post) would be correct to prepare the solution then? I can clarify with the person who wrote the directions by what the 50g refers too (either solute or solution)
 
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