SadStudent
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Homework Statement
Given two moles of some gas with two atoms per molecule which has energy U=aK_{B}T.
Assume the initial pressure is P_{i}= 2 Atm and the initial volume is P_{i}= 0.001\ m^{3}.
Now we heat it in an isochoric process to 2P_{i}.
What would be \Delta T?
What would be the work required to do that?
What would be the change in the gas particles' internal energy?
Homework Equations
U=aK_{B}T
dU=PdS-TdV
The Attempt at a Solution
Well using the first law of thermodynamics, I got that under constant volume dV=0 so \frac{dQ}{dT}=\frac{\partial U}{\partial T} so the entire energy that we spent on heating would be transferred into the gas.
What's a tricky to me is to formulate the change in temperature as a function of pressure because dV=0 so I'd really welcome a hint.
Thanks!
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