Pressure change with constant volume

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SUMMARY

The discussion focuses on calculating the change in temperature (\(\Delta T\)), work done, and internal energy change for a gas undergoing an isochoric process, starting with an initial pressure of \(P_i = 2 \text{ Atm}\) and volume of \(V_i = 0.001 \text{ m}^3\). The gas is heated to a final pressure of \(2P_i\). The first law of thermodynamics is applied, leading to the conclusion that all heat added to the system translates into internal energy change, as the volume remains constant. The participants discuss the implications of assuming the ideal gas law for deriving temperature changes based on pressure.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with isochoric processes in thermodynamics
  • Knowledge of internal energy equations, specifically \(U = aK_{B}T\)
  • Basic principles of the ideal gas law
NEXT STEPS
  • Study the derivation of the ideal gas law and its implications for real gases
  • Explore the relationship between pressure, volume, and temperature in isochoric processes
  • Learn about the mathematical formulation of the first law of thermodynamics
  • Investigate specific heat capacities and their role in internal energy calculations
USEFUL FOR

Students and professionals in physics and engineering, particularly those focusing on thermodynamics and gas laws, will benefit from this discussion.

SadStudent
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Homework Statement


Given two moles of some gas with two atoms per molecule which has energy [itex]U=aK_{B}T[/itex].
Assume the initial pressure is [itex]P_{i}= 2[/itex] Atm and the initial volume is [itex]P_{i}= 0.001\ m^{3}[/itex].
Now we heat it in an isochoric process to [itex]2P_{i}[/itex].

What would be [itex]\Delta T[/itex]?
What would be the work required to do that?
What would be the change in the gas particles' internal energy?

Homework Equations


[itex]U=aK_{B}T[/itex]
[itex]dU=PdS-TdV[/itex]

The Attempt at a Solution


Well using the first law of thermodynamics, I got that under constant volume [itex]dV=0[/itex] so [itex]\frac{dQ}{dT}=\frac{\partial U}{\partial T}[/itex] so the entire energy that we spent on heating would be transferred into the gas.
What's a tricky to me is to formulate the change in temperature as a function of pressure because [itex]dV=0[/itex] so I'd really welcome a hint.

Thanks!
 
Last edited:
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SadStudent said:

Homework Equations



[itex]dU=PdS-TdV[/itex]

Oops, check that.

What's a tricky to me is to formulate the change in temperature as a function of pressure because [itex]dV=0[/itex] so I'd really welcome a hint.

Can you assume the gas obeys the ideal gas law?
 
TSny said:
Oops, check that.Can you assume the gas obeys the ideal gas law?

And yes of course it was a typo :) it's supposed to be [itex]dU=TdS-PdV[/itex]

I'm really not sure whether I can, is there a way of solving this without this assumption?
 
Last edited:

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