Pressure drop across orifice , calculation help

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SUMMARY

The discussion focuses on calculating the pressure drop across an orifice plate and the mass flow rate of a fluid with a relative density of 0.86 and viscosity of 0.003 Pa·s. The orifice plate has a diameter of 6 cm, and the pressure difference measured by a differential U-tube manometer using mercury is 100 mm. The calculations yield a pressure drop of 12,485.2 Pa and a mass flow rate of 8.17 kg/s, while the expected values are 125,000 Pa and 8.39 kg/s, indicating a discrepancy that requires further investigation.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically orifice flow
  • Familiarity with pressure measurement techniques using manometers
  • Knowledge of the Reynolds number and its significance in flow characterization
  • Proficiency in applying Bernoulli's equation and continuity equation in fluid calculations
NEXT STEPS
  • Review the calculation of pressure drop using the equation ΔP = (ρF - ρ)gΔh
  • Study the derivation and application of the volumetric flow rate equation Q = CD A0 √(2(p1 - p2)/(ρ(1 - (A0/A1)²)))
  • Learn about the significance of the coefficient of discharge (CD) in orifice flow measurements
  • Investigate the factors affecting the Reynolds number and its implications for flow regimes
USEFUL FOR

Engineering students, fluid mechanics practitioners, and professionals involved in flow measurement and analysis will benefit from this discussion.

tweety1234
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Homework Statement



A fluid of relative density 0.86 and viscosity 0.003 pa flows through a pipe of 12cm diameter. The flow rate is measured using an orifice plate with a 6cm diameter orifice, with pressure tapping connected to a differential U-tube manometer using mercury (density = 13600 kg m^{-3} ) as the manometer fluid. The coefficient of discharge of the orifice meter is 0.62. The difference in mercury levels in the manometer is 100mm. Calculate the pressure drop across the orifice plate and the mass flow rate of the fluid. Then calculate the Reynolds number Number based on the orifice diameter.

equations needed ;

\bigtriangleup P = (\rho_{F} - \rho) g \bigtriangleup h

Q = \displaystyle C_{D} A_{0} \sqrt{\frac{2(p_{1}-p_{2})}{\rho (1-\frac{A_{0}}{A_{1}}^{2})}

Re = \frac{4M}{\pi D \mu}

mass flow rate Q \rho = m

A_{0} = 0.01131 m^{2}

A_{1} = 2.827 m^{2}

pressure drop = \bigtriangleup P = (\rho_{F} - \rho) g \bigtriangleup h

= (13600-860)9.8 x 0.1 = 12485.2 pa

The correct answer is 125000, I think they may have rounded up ?

2) Volumetric flow rate = (0.62)(0.01131) \sqrt{\frac{(2\times12485.2)}{13600 ( 1-\frac{0.01131}{2.827}^{2})} = 9.50 \times 10^{-3}

mass flow rate = (9.50 \times 10^{-3}) \times 860 = 8.17the correct answer is 8.39 kg s^{-1}

I can't see where I am going wrong, and help appreciated.
 
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