Pressure in fluids and Archimedes' principle

AI Thread Summary
The discussion centers on the effects of placing objects in a container of water regarding buoyant force and pressure. When a piece of wood is added, the volume of displaced water remains unchanged, resulting in constant pressure at the bottom of the container. Conversely, adding a metal object increases the volume of displaced water, thereby increasing the pressure at the bottom. The relationship between displaced water volume and water height is emphasized. Overall, the principles of buoyancy and pressure dynamics are affirmed.
MatinSAR
Messages
673
Reaction score
204
Homework Statement
In following picture, a piece of wood and an empty container are floating on a container of water, and a metal object is at the bottom of the container. A) If we take the piece of wood that is on the surface of the water and put it in the container, how will the pressure at the bottom of the water container change? B) If we take that metal object from its place and put it in a container and the container remains floating, how does the pressure at the bottom of the water container change?
Relevant Equations
Archimedes' principle.
1688481668919.png

Hello.
A: If we put this piece of wood in the emty container, the volume of displaced water will not change (because Buoyant Force has not changed), so the pressure at the bottom of the water container doesn't change and it remains constant.
B: If we put the metal in the emty container, the volume of displaced water should increse (because Buoyant Force has increased), so the pressure at the bottom of the water container is increased.
The volume of displaced water is equivalent to change in water's height.

Am I wrong or not?!
 
Physics news on Phys.org
You are correct.
 
kuruman said:
You are correct.
Thanks again for your help.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top