Pressure inside a soap bubble just under surface

AI Thread Summary
The discussion focuses on calculating the pressure inside a small air bubble just below the water's surface, emphasizing the need to consider both the surrounding pressure and excess pressure. Participants debate whether to use atmospheric pressure or account for hydrostatic pressure due to the water above the bubble. It is clarified that the pressure inside the bubble is the sum of the surrounding pressure and the excess pressure, which includes hydrostatic effects. The importance of understanding the derivation of the pressure formula is highlighted, suggesting that the additional hydrostatic pressure may be negligible for small depths. Ultimately, accurate calculations are essential for determining the pressure in such scenarios.
takando12
Messages
122
Reaction score
5

Homework Statement


What should be the pressure inside a small air bubble of 0.1,, radius,situated just below the surface? st of water=7.2 *10-2 and atmospheric pressure=1.013*105.

Homework Equations

The Attempt at a Solution


I am of the understanding that the pressure inside the bubble is the sum of the surrounding pressure and the excess pressure( 4s/r). But what I don't understand is the surrounding pressure. Should I take the atmospheric pressure? But since it's just below the surface,the top of the bubble would be exposed to atmospheric pressure and the rest of the bubble to whatever pressure the water exerts( I don't think I'm right, I need help). So which pressure is it that I take for external?
 
Physics news on Phys.org
takando12 said:

The Attempt at a Solution


I am of the understanding that the pressure inside the bubble is the sum of the surrounding pressure and the excess pressure( 4s/r). But what I don't understand is the surrounding pressure. Should I take the atmospheric pressure? But since it's just below the surface,the top of the bubble would be exposed to atmospheric pressure and the rest of the bubble to whatever pressure the water exerts( I don't think I'm right, I need help). So which pressure is it that I take for external?
Have you calculated how much difference that makes?
There is another difference between a bubble above the surface and one under the surface which might have rather more significance.
 
haruspex said:
Have you calculated how much difference that makes?
There is another difference between a bubble above the surface and one under the surface which might have rather more significance.
if a bubble was under the surface, the pressure inside the bubble would be 4s/r + the hydrostatic pressure at that height( Pa+hρg).
I am unable to understand what exactly you mean by difference. Since the bubble is just below the surface,will the second term reduce to just Pa?
 
I asked if you had calculated how much difference it makes taking into account that little extra hydrostatic pressure. I mean the numbers, not the algebraic expression. I suspect it is negligible.
takando12 said:
I am unable to understand what exactly you mean by difference.
There is rather an important difference in the forces. Do you know how the ##4\sigma/r## formula is derived? If you follow that through you should see why it is different.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top