How Is Pressure Calculated Underwater?

[iamtrojan3]

Homework Statement

The density of fresh water is 1000 kg/m3. Normal air pressure (i.e., 1 atm) is 1.013(105) Pa. If someone were beneath 25.0 m of water, what pressure would they experience? Give your answer in Pascals and in atmospheres.

Homework Equations

i guess the (density of water)(g)(h)

The Attempt at a Solution

I know its sad... but wat does g stand for? i missed 1 week of class and i have a test 2moro! please help! thanks

 

[radou]

g = 9.81 [m/s^2] = gravitational acceleration.

 

[m2003]

Hello, it seems like you are struggling with understanding the concepts of pressure and density. I would recommend reviewing your notes or textbook and practicing some problems to better understand the equations and concepts. However, to answer your question, g stands for the acceleration due to gravity, which is approximately 9.8 m/s^2 on Earth. Using the given information, we can calculate the pressure experienced by someone beneath 25.0 m of water using the equation P=ρgh, where ρ is the density of water, g is the acceleration due to gravity, and h is the depth of the water. Plugging in the values, we get P=(1000 kg/m^3)(9.8 m/s^2)(25.0 m)=245,000 Pa or 2.42 atm. I hope this helps and good luck on your test tomorrow! Remember to review and practice to improve your understanding.