Pressure -- open a window on a box

AI Thread Summary
To determine the time it takes for the pressure in a box to equal atmospheric pressure after opening a window, the initial conditions include a box volume of 2 m³, an internal pressure of 0.5 KPa, and a temperature of 80°C. The atmospheric conditions are 25°C and 101 KPa. The relevant equations involve calculating the volume of air entering the box (V3) and the flow rate (Q). The formula for time is derived as time = (V1p1)/(p2Q), but the flow rate Q is not clearly defined in the discussion. Clarification on how to determine Q is needed to complete the calculation.
opsops
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Homework Statement



if i have a box of:
volume V1= 2 m3
pressure p1= 0.5 KPa
temperature T1= 80° C
with a window of A=0.2 m2

if i open the window what is the time for pressure box= pressure atmosphere?
temperature atmosphere T2= 25°C
pressure atmosphere P2=101kPa

Homework Equations



Q=V3/time [m3/sec]
V3 volume air goes inside the box

V1p1=V3p3=V3p2
V3=(V1p1)/p2
them
time=V3/Q=(V1p1)/(p2Q)

but Q? i don't understand
 
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Hi opsops. Welcome to Physics Forums. :wink:

That is an interesting question you have. You made it up, did you? :smile:
 
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