Pressure vessels, wall thickness

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SUMMARY

The discussion centers on the design of a cylindrical pressure vessel intended to store 20 m³ of gas at 25 bar. The yield strength of the vessel material is 14,000 psi, which converts to approximately 9.65 MPa. Using a factor of safety of 5, the hoop stress is calculated to be 19.3 MPa, leading to a required wall thickness of 231 mm. The analysis concludes that the vessel should be treated as a thick-walled cylinder due to the calculated thickness exceeding the criteria for thin-walled assumptions.

PREREQUISITES
  • Understanding of pressure vessel design principles
  • Knowledge of material yield strength and safety factors
  • Familiarity with hoop stress calculations
  • Basic geometry related to cylindrical shapes
NEXT STEPS
  • Study ASME Boiler and Pressure Vessel Code for design standards
  • Learn about the differences between thin-walled and thick-walled pressure vessels
  • Explore advanced calculations for pressure vessel wall thickness
  • Investigate material selection criteria for pressure vessels
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Mechanical engineers, pressure vessel designers, and students studying fluid mechanics or materials science will benefit from this discussion.

Big Jock
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20 m3 of gas at a pressure of 25 bar is to be stored in a cylindrical
pressure vessel 2 m long. Given the following information :
The yield strength of the vessel material is 14,000 psi
If a factor of safety of 5 is to be used, determine:

(a) Whether the vessel should be treated as a thin or thick cylinder.
(b) The wall thickness required for the pressure vessel

The information I have gathered to date is

14,000psi= 14,000 / 0.14503773773=9.6526602 x 10^6 Pa
20m^3=20,000Litres
Pressure of gas=25bars-2500kpa=2.5 x 10^6
V=∏r^2h
r=√v/∏h=1.784 Metres
D=2r=3.568 Metres


These are all the values I have at the moment. Hopefully as I continue to try and solve it solve kind soul may see this post and give me a nudge in the right direction. Many thanks in advance...
 
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Hoop stress= yield strength / safety factor = 19.3 x 10^6
thickness= pr/hoop stress = 0.231m =231mm
so I conclude that the cylinder is thick walled and is a 7.222
and the minimum wall thickness must be 231mm

Could someone tell if this is correct and answers the questions suitably please
 

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