Projectile Motion, A study of height and time

AI Thread Summary
The discussion centers on a physics problem involving projectile motion, specifically a rocket launched at 97.0 m/s at a 53.0° angle, aimed at a 27.0 m high wall located 24.0 m away. The calculations provided show that the rocket reaches a height of 31 m at the wall, suggesting it clears the wall by 4.00 m. However, there is uncertainty about the accuracy of these calculations, with participants questioning whether an error exists. The conversation highlights the importance of verifying calculations in physics problems and suggests that the solution may need reevaluation. Ultimately, the accuracy of the initial calculations is in question, prompting a call for further analysis.
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A Cutnell and Johnson Physics question illustrates a rocket launch:

A rocket is fired at a speed of 97.0 m/s from ground level, at an angle of 53.0 ° above the horizontal. The rocket is fired toward an 27.0-m high wall, which is located 24.0 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?

My Calculations:

Vo = 97.0 m/s
Theta = 53 degrees
x = 24 m
y = 27 m
Let H illustrate the height of the rocket at point x on the axis.
t = ?
a = -9.80 m/s ^2

Vo sin 53 = Voy = 77.46
Vo cos 53 = Vox = 58.37

x = Vox(t)
t = x/Vox = 24/58.37 = .411 s

H = Voy(t) + .5 a(t^2)

Plug and Chug

H = 77.46(.411) + .5(-9.80)(.411^2) = 31 m

Distance Rocket clears wall = 31m-27m = 4.00 m <-----Incorrect.

Is there a problem with my calculations that I am not understanding?
 
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How do u no ur wrong? Looks ok 2 me unless I am makin exactly the same mistake. Mayb ur lookin under the wrong chapter at the back of the book 4 ur answers!?
 
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