Projectile Motion Using Vectors

AI Thread Summary
The discussion centers around solving a projectile motion problem involving a ball shot into the air with given horizontal and vertical velocities. Participants clarify that the velocities should be treated separately rather than combined, emphasizing the importance of using kinematic equations for both horizontal and vertical motion. The initial confusion regarding vector notation is addressed, confirming that the velocities are indeed 7.1 m/s horizontally and 6.1 m/s vertically. Users suggest writing down all relevant equations and known values to facilitate solving for maximum height and horizontal distance. Overall, the focus is on correctly interpreting vector notation and applying kinematic principles to find the required solutions.
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Homework Statement



A ball is shot from the ground into the air. At a height of 8.7 m, its velocity is = 7.1 + 6.1 m/s, with horizontal and upward. (a) To what maximum height does the ball rise? (b) What total horizontal distance does the ball travel? What are the (c) magnitude and (d) angle (below the horizontal; give as negative) of the ball's velocity just before it hits the ground?


Homework Equations


The Kinematics equations


The Attempt at a Solution


im really not sure how to start this problem... do i take the square root of 7.1^2 + 6.1^2 and use that as V0x and Vx, then solve for T? This is one of the last questions i need on wileyplus to get over a 9/10 on homework...

Ive looked at the practice exam for wednesday and its sooo muche easier than these problems. might be freaking out for no reason??

Thanks.
 
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its velocity is = 7.1 + 6.1
This is not very clear. Does it mean the velocity is 13.2, or does it mean the horizontal velocity is 7.1 and the vertical velocity 6.1? Check to see if you have typed it in correctly.

Assuming Vx = 7.1 and Vy = 6.1, you could use these as the initial velocities in the equations for horizontal and vertical motion to find anything you like. No, you would not combine 7.1 and 6.1 with the Pythagorean theorem - you need the horizontal and vertical parts separately to put in the equations.
 
Delphi51 said:
This is not very clear. Does it mean the velocity is 13.2, or does it mean the horizontal velocity is 7.1 and the vertical velocity 6.1? Check to see if you have typed it in correctly.

Assuming Vx = 7.1 and Vy = 6.1, you could use these as the initial velocities in the equations for horizontal and vertical motion to find anything you like. No, you would not combine 7.1 and 6.1 with the Pythagorean theorem - you need the horizontal and vertical parts separately to put in the equations.

the problem didnt copy right..

7.1 i + 6.1 j so yes, horizontal is first, vertical is second.
 
Excellent. Do you know the equation for the horizontal motion (constant speed) and the distance and speed equations for the vertical motion (accelerated)? It is a good idea to write down all three, put in all the numbers you know and then try to solve one of the equations to find out something you didn't already know. Part (a) asks about maximum height, where you know the vertical velocity.
 
Delphi51 said:
Excellent. Do you know the equation for the horizontal motion (constant speed) and the distance and speed equations for the vertical motion (accelerated)? It is a good idea to write down all three, put in all the numbers you know and then try to solve one of the equations to find out something you didn't already know. Part (a) asks about maximum height, where you know the vertical velocity.

im just confused for the vector notation of direction. i know how to take the equations and solve for what i need. the velocity given in vector noation is throwing me off.
 
7.1 i + 6.1 j
Just a way of giving you the horizontal and vertical velocity.
Solve it just the way you did in grade 11.
 
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