Projectiles physics problem - due tomorrow ;_;

AI Thread Summary
The discussion revolves around a projectile that splits into two pieces after reaching its apex, and the user seeks help in determining the initial velocities of these pieces in relation to the original velocity and angle. The user has attempted to apply conservation of kinetic energy and momentum but is struggling to incorporate the angle theta into their equations. It is clarified that kinetic energy cannot be conserved in this scenario, emphasizing that the problem primarily relies on conservation of momentum. The user is encouraged to focus on momentum conservation to derive the velocities, as the change in kinetic energy cannot be calculated without first determining these velocities. The conversation highlights the importance of correctly applying physics principles to solve projectile motion problems.
voodoodoodoo
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hey everybody, i would really appreciate a little help with this.

I have a projectile, labeled zero, with mass m and velocity V. it travels in a parabolic motion until it reaches its apex, at which point it divides into two equal pieces, 1 and 2, with mass m/2 and m/2. Each of these pieces splits off with a velocity theta degrees from the horizontal.

Now, i need to determine V1 initial and V2 initial in terms of V, theta, and unit vectors i^ and j^.

Any help at all would really be appreciated - i have AIM(antigravityjesus) and MSN (antigravityjesus@hotmail.com).
Thanks!
 
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oh, forgot to say, this is the third part - i already found Delta K / K initial and solved some change-in-K relative to Theta equations.

The problem is, if i sub kinetic energy = kinetic energy into conservation of momentum, i get V = V.

Can i somehow use my Delta K/K equation here? I am at a loss.

Thanks.
 
okay, this is what I've done:

1/2 m V^2 = 1/2 m 1/2 v1i ^ 2 + 1/2 m 1/2 v2i ^ 2
which equates to
V^2 = v1i^2 + v2i^2 / 4mV = mv1/2 + mv2/2
which equates to
V = (v1+v2)/2
V^2 = (v1^2 + 2v1v2 + v2^2)/4
... which doesent directly equal v1i^2 + v2i^2 / 4 ... neat. let me see if i just accidentally solved something!

The problem is, i don't have any equations with theta in it.
 
nope, just gives me v1=0 and v2=0. darn.
 
voodoodoodoo said:
okay, this is what I've done:

1/2 m V^2 = 1/2 m 1/2 v1i ^ 2 + 1/2 m 1/2 v2i ^ 2
which equates to
V^2 = v1i^2 + v2i^2 / 4


mV = mv1/2 + mv2/2
which equates to
V = (v1+v2)/2
V^2 = (v1^2 + 2v1v2 + v2^2)/4
... which doesent directly equal v1i^2 + v2i^2 / 4 ... neat. let me see if i just accidentally solved something!

The problem is, i don't have any equations with theta in it.
Kinetic energy cannot be conserved in this process. It is first a conservation of momentum problem. If the angle θ is given, or your answers are supposed to be expressed in terms of θ then all you need is conservation of momentum.
voodoodoodoo said:
oh, forgot to say, this is the third part - i already found Delta K / K initial and solved some change-in-K relative to Theta equations.

The problem is, if i sub kinetic energy = kinetic energy into conservation of momentum, i get V = V.

Can i somehow use my Delta K/K equation here? I am at a loss.

Thanks.
You can't find the change in kinetic energy without using momentum conservation to find the velocites, so I really don't get what you are saying here.
 
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