Proper free-body diagram for a shaft experiencing multiple torques

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Qube
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Homework Statement
Draw a FBD, determine the largest torque, T1, and find shear stresses in CD and DE
Relevant Equations
Method of sections, static equilibrium
shear stress=Tc/J
Textbook figure of a solid shaft with labelled points E, D, C, B and A, carrying torques of 300 N·m at D, 600 N·m at C, 900 N·m at A, and an unknown torque T1 at C.


I wish to draw a proper free-body diagram for this shaft. However, my FBD does not agree with the solutions manual. If someone could point out where I erred, that would be great.

This is what I drew:

Handwritten free-body diagram of a shaft divided into sections A to D, each drawn as a rectangle with curved torque arrows at both ends: A shows 900, B shows 900-T1, C shows 1500-T1, D shows 1800-T1.


From my FBD, it is clear that the maximum torque is present in section DE of the shaft.

We can use the equation shear stress=Tc/J in conjunction with the maximum allowed shear stress of 60 MPa as follows:

Equation: tau = Tc/J = (1800 - T1) * 0.025 m divided by (pi/4) * 0.025^4 m^4, less than or equal to 60 MPa, giving T1 = 1063.69 Nm.


Then, to find the maximum shear stresses in sections CD and DE:

Two worked equations for shear stress in shaft sections: tau_CD = Tc/J = (1500 - T1)*0.025m / ((pi/4)*0.0254 m^4) = (1500 - 1063.69)*0.025m / (same) = 35.5 MPa; tau_DE = (1800 - T1)*0.025m / ... = (1800 - 1063.69)*0.025m / ... = 60.0 MPa.
 
Attachments
  • Textbook figure of a solid shaft with five torque arrows: 300 N·m at end E, 600 N·m at a point between D and C, T1 at a point between C and B, and 900 N·m at end A, with labelled points E, D, C, B and A along the shaft.
    1601854234002.png
    33.9 KB · Views: 472
  • Handwritten free-body diagram with four labeled sections A to D, each a rectangle with curved arrows at each end showing torques: A shows 900 at both ends, B shows 900-T1, C shows 1500-T1, D shows 1800-T1.
    1601854416725.png
    75.4 KB · Views: 276
  • Handwritten equation: tau = Tc/J, the torsion shear stress formula, with T over c and J as fractions.
    1601854526177.png
    815 bytes · Views: 289
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Are you sure about the ##\frac{\pi}4##s? I thought it was ##\frac{\pi}2##
 
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Thanks! You are right, it is J=pi*c^4/2. I will rework this problem and see if I get the right answer this time...
 
Qube said:
Thanks! You are right, it is J=pi*c^4/2. I will rework this problem and see if I get the right answer this time...
Note that with your original calculation the 900Nm was already too much for AB.
 
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Okay, I reworked the problem. I drew a torque diagram.

Hand-drawn torque diagram plotting T (N.m) against shaft positions A to E, with steps of 1800 - T1, 1500 - T1, 900 - T1 and 900 N.m, plus handwritten shear stress calculation.


It seems that the maximum possible value of the unknown torque, T1, is 327 Nm.

From there, it seems that the internal shear stress in section CD is about 47 MPa, and the internal torque in DE causes the bar to hit its shear stress limit, 60 MPa.

Two shear stress calculations written as equations: tau CD = Tc/J = (1500 - T1) * 0.025 m / ((pi/2) * 0.025^4 m^4) = (1500 - 327.378) * 0.025 / ((pi/2) * 0.025^4) = 47.776 MPa; and tau DE = Tc/J = (1800 - T1) * 0.025 m / ((pi/2) * 0.025^4 m^4) = (1800 - 327.378) * 0.025 / ((pi/2) * 0.025^4) = 60.0 MPa.


This makes much more sense than my initial results.

Does it make sense that the section with the highest shear stress is the section of the bar closest to the wall, to which the bar is anchored?

Also, does my torque diagram make sense? Someone else argues that this is the correct diagram:

Torque diagram T (N.m) against x for shaft sections A to E: 900 from A to B, -1472.62 from B to C, -872.62 from C to D, and -572.62 from D to E.
 
Qube said:
Okay, I reworked the problem. I drew a torque diagram.

View attachment 270516

It seems that the maximum possible value of the unknown torque, T1, is 327 Nm.

From there, it seems that the internal shear stress in section CD is about 47 MPa, and the internal torque in DE causes the bar to hit its shear stress limit, 60 MPa.

View attachment 270517

This makes much more sense than my initial results.

Does it make sense that the section with the highest shear stress is the section of the bar closest to the wall, to which the bar is anchored?

Also, does my torque diagram make sense? Someone else argues that this is the correct diagram:

View attachment 270518
What, exactly, is the inequality involving 1800 - T1 that you deduce from your diagram?
What will happen to your diagram if T1 is increased a little?
What would happen if T1 were zero?
 
Okay, scratch all that. I managed to figure it out by finding similar problems. Thank you for the guidance. I hope that this post of mine is error-free!

Diagram of a horizontal shaft fixed at end E with torque arrows at points D, C, B and A; labels read 300 N·m at D, 600 N·m at C, 900 N·m at A, and T1 at B.

We need to start by applying the right-hand rule to the applied torques, with the sign convention that a torque directed away from point E is a positive torque. This means A, C, and D are positive, and the unknown torque at B (T1) is a negative torque.

With the above established, we can find the internal torque in segment AB, knowing that the segment is in equilibrium:

Equilibrium equation for shaft segment AB: sum of T = 0; 900 - T1 + TAB = 0, which gives TAB = T1 - 900.


We also know that the maximum allowable shear stress in any segment is 60 MPa, which allows us to find the maximum value of T1:

Equations for maximum shear stress in a shaft: tau_allow = 60 MPa = T_AB c / J = (T1 - 900)(0.025) / (pi/2 (0.025)^4), leading to T1 <= 2372.62 Nm.

Using the above information, and the fact that every section of the bar is in equilibrium, we can find the internal torques of each section.

Knowing the internal torques of sections CD and DE allow us to find the maximum shear stresses within CD and DE.
 
That's unnecessarily rewriting what you did successfully in post #5 by other means.
You found that the torques are, taking some sign convention, 900, 900-T, 1500-T, 1800-T.
The constraint is some maximum magnitude torque, Tmax. What is the correct way to write that algebraically?
 
haruspex said:
You found that the torques are, taking some sign convention, 900, 900-T, 1500-T, 1800-T.
The constraint is some maximum magnitude torque, Tmax. What is the correct way to write that algebraically?

I don't understand, but I'll give it a try.

Are you saying to plug 900-T, 1500-T, and 1800-T into the equation, shear=Tc/J and try to maximize the value of T?
 
Qube said:
I don't understand, but I'll give it a try.

Are you saying to plug 900-T, 1500-T, and 1800-T into the equation, shear=Tc/J and try to maximize the value of T?
No, I am asking how you express in algebra that, e.g., the torque 1500-T must not exceed the calculated limit (call it Tmax)? Be careful.
 
1500-T<Tmax

Handwritten-style inequality: 1500 − T < T_max < τJ/c, with T_max and the fraction τJ over c as typed in the image.


I'm still unclear on what you mean, sorry.
 
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haruspex said:
It's magnitudes!

I don't see a direct constraint on Tmax in this problem that is given. I'm still unclear on what you mean by:

The constraint is some maximum magnitude torque, Tmax. What is the correct way to write that algebraically?

The only constraint I see is on torsional shear, which is a function of Tmax.
 
Qube said:
I don't see a direct constraint on Tmax in this problem that is given. I'm still unclear on what you mean by:
The only constraint I see is on torsional shear, which is a function of Tmax.

I was using Tmax to mean the maximum torsional shear, not the max value of T1.
I'll stop trying to be subtle. You computed 900-T1, 1500-T1, and 1800-T1, and took the constraint to be that each < Tmax. In fact, the constraint is on the magnitudes of these: |900-T1|<Tmax, |1500-T1|<Tmax, and |1800-T1|<Tmax. That opens up more possibilities.