Proton moving in magnetic field

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Homework Help Overview

The discussion revolves around a proton moving in a magnetic field, specifically examining the direction and magnitude of the force acting on it. The proton is traveling in the +z direction with a given speed, while the magnetic field is oriented in the +x direction.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the right hand rule to determine the direction of the force and question the appropriate formula for calculating the force on a charged particle in a magnetic field. There is also mention of the left hand rule and its implications for the direction of force.

Discussion Status

Participants are exploring different methods to determine the force on the proton, with some suggesting the right hand rule and others referencing the left hand rule. There is an ongoing examination of the relevant equations and their implications for the problem, but no consensus has been reached regarding the correct approach.

Contextual Notes

Participants note the absence of specific equations in the original post and question the assumptions regarding the application of the right and left hand rules in this context.

sdevoe
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Homework Statement


At a particular instant a proton is traveling in the +z direction, with speed 4105 m/s. At the location of the proton there is a magnetic field of magnitude 0.25 T in the +x direction, due to current running in a nearby coil.
what is the direction and magnitude of force on the proton?

Homework Equations


none i think?


The Attempt at a Solution


Do you use the right hand rule possibly?
 
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The right hand rule can give you the direction of the force, but not the magnitude.

What equation do you know that gives the force on a charged particle of charge q moving with velocity v in a magnetic field of strength B?
 
Try to find out the formula for the force on a charged particle in a magnetic field. The direction of the field is given by the left hand rule.
 
the equation is F=qvB but then using the left hand rule since it is a proton would give me negative y direction if I'm not mistaken and that is incorrect?
 
You can use either right handed screw rule or Flemming's left hand rule.
 

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