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Proving an equation

  1. Mar 11, 2008 #1
    1. The problem statement, all variables and given/known data
    Prove that tan^2θ - sin^2θ = tan^2θsin^2θ


    2. Relevant equations
    I'm not sure :S


    3. The attempt at a solution
    I have no idea
     
  2. jcsd
  3. Mar 11, 2008 #2

    Kurdt

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    What is the definition of tan?
     
  4. Mar 11, 2008 #3
    tan = sin^2θ/cos^2θ

    ?
     
  5. Mar 11, 2008 #4

    Kurdt

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    [tex] \tan (\theta) = \frac{\sin(\theta)}{\cos(\theta)} [/tex]

    so

    [tex] \tan^2 (\theta) = \frac{\sin^2(\theta)}{\cos^2(\theta)} [/tex]

    You will then need to manipulate one side until it equals the other using basic trigonometric identities.
     
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