Pulley Free Body Diagram and rope tension

AI Thread Summary
The discussion focuses on calculating the tension in a rope supporting an 80 kg person and a 20 kg platform using free body diagrams (FBD). The correct tension is determined to be 500 N, as the total weight of the system is 1000 N, leading to the equation 2T = 1000 N. Participants emphasize the importance of accurately isolating the system in the FBD, noting that forces acting on the system must be clearly identified. The need for clarity in drawing the FBD is highlighted, particularly in distinguishing between internal and external forces. Properly constructed FBDs will help in solving for the tension in the ropes effectively.
armoredhalo00
Messages
2
Reaction score
0

Homework Statement




The figure above shows an 80 kilogram person standing on a 20 kilogram platform suspended by a rope passing over a stationary pulley that is free to rotate. The other end of the rope is held by the person. The masses of the rope and pulley are negligible. You may use g = 10 m/ s2. Assume that friction is negligible, and the parts of the rope shown remain vertical.
a. If the platform and the person are at rest, what is the tension in the rope?



My problem is that I'm not identifying the direction of the forces in the free body diagram.

On the left side of the pulley i have this: The Mg of the platform and the person doing down and the Tension of the rope going up. On the other side of the pulley I have the force of the person holding the rope down and the Tension of the rope up. (This is where I feel I'm wrong I just need an explanation if I am)

As result I get the T=1000N.

Homework Equations




The Attempt at a Solution



I know the answer is T= 500 N because the equation is supposed to be 2T=1000N
 
Physics news on Phys.org
You are not drawing your FBD's correctly. In a FBD, you isolate all or part of the system, and note the forces acting on that isolated system. Forces that may be internal to the entire system become external to the isolated system. Try drawing a FBD that isolates the person/platform from the pulley, a diagram which cuts through both ropes and encircles the man and platform. Identify all forces acting, and use Newton 1.
 
Is this right Phantom?

I have on the left side of the pulley the mg of the platform and person countered by the Tension up.

On the right side i have a force down. So i suppose that that Force down which is given by the person is also Tension.

Thus 2T=1000N
 
The forces in their respective components should be balanced out if the system of particles is at equilibrium.
 
armoredhalo00 said:
Is this right Phantom?

I have on the left side of the pulley the mg of the platform and person countered by the Tension up.

On the right side i have a force down. So i suppose that that Force down which is given by the person is also Tension.

Thus 2T=1000N
Are you drawing a FBD of the pulley? Your wording is not clear to me. When you draw a FBD, draw a circle around the part of the system you want to isolate. Wherever that circle 'cuts' through a contact point, there is a force there. Also, the weight force, if any, is always external to that isolated system. So if you draw a FBD of the pulley, you have 2 equal tension forces acting down, and the tension in the ceiling cord acting up. That tells you that the tension in the ceiling cord is twice the tension in each of the lower cords (per Newton 1). Now by drawing a FBD that encircles the person and platform and upper ceiling cord, you can solve for the upper ceiling cord tension and then solve for the lower rope tension. But it is easier to draw a FBD that encircles the man and platform and 2 cords to solve for the tension in the cords supporting the man and platform.
 
armoredhalo00 said:
...

My problem is that I'm not identifying the direction of the forces in the free body diagram.

Can you scan your FBD and post it? That would be a big help.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Is it friction or tension acting on the person hanging on a rope?
Replies
4
Views
1K
Monkey accelerating up and down a rope
Replies
38
Views
4K
Falling mass, additionally accelerated by a rope
Replies
18
Views
1K
Problem with pulleys - two fixed and one movable
Replies
22
Views
319
Mechanical advantage of a pulley system
Replies
2
Views
1K
Leg suspended in a traction system
Replies
18
Views
5K
Calculating acceleration of a prism and block connected to a wall through a rope and pulley
Replies
4
Views
332
System of two pulleys and three masses
Replies
22
Views
6K
What is the tension in the rope?
Replies
16
Views
7K
How Does Nick's Acceleration Change When His Friend Pulls the Rope?
Replies
6
Views
3K

Hot Threads

Recent Insights

Back
Top